Chapter 11.2, Problem 4ACYP

To determine

To find: The value of $x$ .

Answer to Problem 4ACYP

The value of $x=8.36\text{in}$ .

Explanation of Solution

Given:

The given diagram is shown in Figure 1

  

Figure 1

Calculation:

The given figure is in the shape of the rhombus and the area of the rhombus is in the form,

  $A=\frac{1}{2}{d}_1{d}_2$

Then,

  $\begin{array}{l}92{\text{in}}^2=\frac{1}{2}\left(22\text{in}\right)\left(x\text{in}\right)\\ 92{\text{in}}^2=11x{\text{in}}^2\\ x=8.36\text{in}\end{array}$