Explanation Given Information: The function is s = t e t 2 . Formula used: If f ( x ) = c ⋅ u ( x ) , where, c is a constant and u ( x ) is a differentiable function of x , then, f ′ ( x ) = c ⋅ u ′ ( x ) Where, u is a differentiable function of x , According to the property of derivatives, if y = e x , d y d x = e x According to the power rule of differentiation, d y d x = n x n − 1 According to the product rule of derivatives, for a function of type y = f ⋅ g , the derivative is d y d x = f ′ ⋅ g + f ⋅ g ′ Calculation: Consider the function provided, s = t e t 2 Differentiate both sides with respect to t , d s d t = d d t ( t e t 2 ) Apply the product rule of derivatives, d s d t

11th Edition

ISBN: 9781305713864

Author: HARSHBARGER

Publisher: CENGAGE L

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Chapter 11.2, Problem 3CP

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To calculate: The value of dsdt for the function s=tet2.

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Chapter 11.2, Problem 2CP

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Chapter 11 Solutions

MATHEMATICAL APPLICATIONS FOR PKG

Ch. 11.1 - 1. Ch. 11.1 - 2. If Ch. 11.1 - Prob. 3CP Ch. 11.1 - 4. Find . Ch. 11.1 - Prob. 1E Ch. 11.1 - Prob. 2E Ch. 11.1 - Prob. 3E Ch. 11.1 - Prob. 4E Ch. 11.1 - Prob. 5E Ch. 11.1 - Find the derivatives of the functions in Problems...

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The value of d s d t for the function s = t e t 2 .

Solution Summary: The author explains how to calculate the value of ds dt for the function s=t

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To calculate: The value of dsdt for the function s=tet2.

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