Explanation Given: The diameter of the two smaller pipes are 1 1 4 ′ ′ . The area of the larger pipe approximately the sum of the areas of the 2 smaller pipes. Calculation: The given diameter of the two smaller pipes are 1 1 4 ′ ′ . Note that the area of a circle is π r 2 where r is the radius. Here radius is 1 1 4 ′ ′ ( 1 2 ) . So obtain the area of a smaller pipe as follows. A = π r 2 = π ( 1 1 4 × 1 2 ) 2 = π ( 5 8 ) 2 ≈ 1.23 Sum of the area of 2 smaller pipes is 2 A . That is, 1.22718 ( 2 ) ≈ 2.45437

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ISBN: 2818440003295

Author: CARMAN

Publisher: PEARSON CP

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Chapter 11.2, Problem 16CE

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To find: The minimum diameter of the larger pipe.

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Chapter 11.2, Problem 15CE

Chapter 11.2, Problem 17CE

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Chapter 11 Solutions

MYLAB MATH FOR MATHEMATICS FOR THE TRAD

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The minimum diameter of the larger pipe.

Solution Summary: The author calculates the minimum diameter of the larger pipe and the area of a smaller pipe by treating the diameter as d.

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