BASIC BIOMECHANICS
8th Edition
ISBN: 9781259913877
Author: Hall
Publisher: RENT MCG
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Chapter 11, Problem 9AP
A hammer is being accelerated at 15 rad/s2. Given a radius of rotation of 1.7 m, what are the magnitudes of the radial and tangential components of acceleration when tangential hammer speed is 25 m/s? (Answer: ar = 367.6 m/s2; at = 25.5 m/s2)
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The “mean-speed theorem” for calculating average velocity under constant acceleration, developed by Thomas Bradwardine and the Mertonian Calculators at Oxford University, is expressed algebraically as:
density = weight/volume
(m1)(v1) = (m2)(v2)
C. (vm) = 1/2 (v0 + vf)
s = (v0)(t) + 1/2 (a)(t2)
velocity = distance/time
Chapter 11 Solutions
BASIC BIOMECHANICS
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Ch. 11 - Explain how the velocity of the ball in Problem 4...Ch. 11 - A majorette in the Rose Bowl Parade tosses a baton...Ch. 11 - A cyclist enters a curve of 30-m radius at a speed...Ch. 11 - A hammer is being accelerated at 15 rad/s2. Given...Ch. 11 - A speed skater increases her speed from 10 m/s to...
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- The “mean-speed theorem” for finding average velocity under constant acceleration, proposed by the Oxford Calculators, and demonstrated geometrically by Nicole Oresme, is expressed algebraically as: density = weight/volume (m1)(v1) = (m2)(v2) (vm) = 1/2 (v0 + vf) s = (v0)(t) + 1/2 (a)(t2) velocity = distance/timearrow_forwardBased on the acceleration in the above ball rolling down an inclined plane (with vo = 0 meters per second), how far would it have traveled along the inclined plane in the first six seconds of rolling? 9 meters 16 meters 25 meters 36 meters 49 metersarrow_forwardAn airplane flying directly eastward at a constant speed travels 293 km in 2.0 h. (a) what is the average velocity of the plane? (b) what is the instantaneous velocity?arrow_forward
- From the equation of a lineweaver-burke plot, calculate Km and Vmax. Show your work and include units. The equation is y=393.4x +8.4337arrow_forwardWhen Galileo Galilei rolled a ball down an inclined plane, it traveled 1.0 meters in the first second, and a total of 4.0 meters in the first two seconds. What was its acceleration on this inclined plane? 2.0 meters per second2 3.0 meters per second2 4.0 meters per second2 5.0 meters per second2 6.0 meters per second2arrow_forwardUsing the Michaelis-Mentan graph pictured (graphing initial velocity and PNPP concentration), identify Vmax and Km as well as possible. Then, using the Lineweaver-Burk graph (graphing 1/Vo and 1 / PNPP concentration), label the reciprocals of Vmax and Km on the graph and use them to calculate Km and Vmax.arrow_forward
- 72. Find J and K in the rotational system shown in Figure P4.18 to yield a 30% overshoot and a sett- ling time of 3 seconds for a step input in torque. [(Section: 4.6] 000 K FIGURE P4.18arrow_forwardIn terms of mass and acceleration, what is the equation for force?arrow_forwardA scientist was investigating if differences in the frictional work performed on a model car can change depending on its mass (in grams) and whether the car moves up or down an inclined plane. They decided to measure the amount of frictional force experienced by the model car and the distance it traveled in meters. The scientists were able to evaluate the frictional work using the following data. Mass (g) Distance (m) Force Work Done by Friction (J) car going up the incline 100 39 0.063 2.457 car going down the incline 70 39 0.2309 ? It is known that the relationship between force and distance determines the work done by friction (W+). W₁ = fd Wf work done by friction f = force d = distance Question: How much work done by friction was exerted on the car as it moved down the inclined plane? You may use a calculator. 1 2.457 9.005 11.46 16.16 PREVIOUS FINISHarrow_forward
- Solve using Instantaneous Center of Zero Velocityarrow_forwardUsing the above “mean-speed theorem”, calculate the average velocity of a car with constant acceleration from 0 km/hour (initial speed) to 80 km/hour (final speed) over a 5-minute period of time. average velocity over 5 minutes = 16 kilometers/hour average velocity over 5 minutes = 20 kilometers/hour average velocity over 5 minutes = 24 kilometers/hour average velocity over 5 minutes = 32 kilometers/hour average velocity over 5 minutes = 40 kilometers/hourarrow_forwardAccording to Jean Buridan’s equation, the momentum or “impetus” of an 8 kilogram mass moving at 48 meters per second would be: 192 kilogram-meters per second 384 kilogram-meters per second 576 kilogram-meters per second 768 kilogram-meters per second 960 kilogram-meters per secondarrow_forward
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