Chapter 11, Problem 94IE

(a)

Interpretation Introduction

Interpretation: If the pressure in the tank is greater or lesser than the atmospheric pressure should be explained and the dependence of pressure on the amount of liquid butane should be explained.

Concept Introduction: Boiling point is the temperature at which pressure is equal to atmospheric pressure.

(b)

Interpretation Introduction

Interpretation:The change in temperature of the liquid, if the valve of the tank is opened and few liters of gas are allowed to escape should be explained.

Concept Introduction: Boiling is an endothermic process that is heat is absorbed by the surrounding in to evaporate the liquid.

(c)

Interpretation Introduction

Interpretation: The heat required vaporizing $25\text{0}\text{g}$ of butane and the volume occupied by the butane at $750\text{torr}$ and $3\text{5}\text{°C}$ should be determined.

Concept Introduction: Molar mass of butane is calculated by the formula,
 $M=\left(N_{\text{C}}\times M_{\text{C}}\right)+\left(N_{\text{H}}\times M_{\text{H}}\right)$

Where,

• $M$ is the molar mass of butane.
• $N_{\text{C}}$ is the number of carbon atoms in butane $\left(4\right)$ .
• $N_{\text{H}}$ is the number of hydrogen atoms in butane $\left(10\right)$ .
• $M_{\text{C}}$ is the atomic mass of carbon $\left(12.01\text{g/mol}\right)$ .
• $M_{\text{H}}$ is the atomic mass of hydrogen $\left(1.01\text{g/mol}\right)$ .

Number of moles of butane is calculated by the formula,
$n=\frac{m}{M}$

Where,

• $m$ is the mass of butane.
• $M$ is the molar mass of butane.