Explanation Formula used: “The standard normal variable is given by, z = x − μ σ , where µ is the mean and σ is the standard deviation”. Calculation: Given that, the mean and standard deviation are 100 and 10 respectively. Compute the value of z by using above formula. z = x − μ σ = 100 − 100 10 = 0 10 = 0 Use Normal distribution table, the area corresponds to the left of z = 0 is 0.00. Similarly, find z for the value of the variable x = 118 . z = x − μ σ = 118 − 100 10 = 18 10 = 1

MyLab Math with Pearson eText - Stand Alone Access Card - for Calculus for Business, Economics, Life Sciences & Social Sciences, Brief Version (14th Edition)

14th Edition

ISBN: 9780134856599

Author: Raymond A. Barnett, Michael R. Ziegler, Karl E. Byleen, Christopher J. Stocker

Publisher: PEARSON

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Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 11, Problem 8RE

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To find: The probability P(100≤X≤118).

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Chapter 11, Problem 7RE

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Chapter 11 Solutions

MyLab Math with Pearson eText - Stand Alone Access Card - for Calculus for Business, Economics, Life Sciences & Social Sciences, Brief Version (14th Edition)

Ch. 11.1 - Evaluate the following, if it converges: 3dx(x1)2.Ch. 11.1 - Prob. 2MP Ch. 11.1 - Prob. 3MP Ch. 11.1 - Prob. 4MP Ch. 11.1 - Prob. 5MP Ch. 11.1 - Prob. 6MP Ch. 11.1 - Prob. 1ED Ch. 11.1 - Prob. 2ED Ch. 11.1 - Prob. 1E Ch. 11.1 - Prob. 2E

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The probability P ( 100 ≤ X ≤ 118 ) .

Solution Summary: The author calculates the value of the probability P(100le X le 118 ) by using the formula.

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To find: The probability P(100≤X≤118).

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Chapter 11 Solutions