A point in three-dimensional space can be represented in a three-dimensional coordinate system . In such a case, a z -axis is taken perpendicular to both the x - and y -axes . A point P is assigned an ordered triple P x , y , z relative to a fixed origin where the three axes meet. For Exercises 83-86, determine the distance between the two given points in space. Use the distance formula d = x 2 − x 1 2 + y 2 − y 1 2 + z 2 − z 1 2 . 6 , − 4 , − 1 and 2 , 3 , 1
A point in three-dimensional space can be represented in a three-dimensional coordinate system . In such a case, a z -axis is taken perpendicular to both the x - and y -axes . A point P is assigned an ordered triple P x , y , z relative to a fixed origin where the three axes meet. For Exercises 83-86, determine the distance between the two given points in space. Use the distance formula d = x 2 − x 1 2 + y 2 − y 1 2 + z 2 − z 1 2 . 6 , − 4 , − 1 and 2 , 3 , 1
Solution Summary: The author explains the formula for the distance between the two points (6,-4,-1) and
A point in three-dimensional space can be represented in a three-dimensional coordinate system. In such a case, a
z
-axis
is taken perpendicular to both the
x
- and
y
-axes
.
A point
P
is assigned an ordered triple
P
x
,
y
,
z
relative to a fixed origin where the three axes meet. For Exercises 83-86, determine the distance between the two given points in space. Use the distance formula
d
=
x
2
−
x
1
2
+
y
2
−
y
1
2
+
z
2
−
z
1
2
.
6
,
−
4
,
−
1
and
2
,
3
,
1
System that uses coordinates to uniquely determine the position of points. The most common coordinate system is the Cartesian system, where points are given by distance along a horizontal x-axis and vertical y-axis from the origin. A polar coordinate system locates a point by its direction relative to a reference direction and its distance from a given point. In three dimensions, it leads to cylindrical and spherical coordinates.
-6 -5
*
10
8
6
4
2
-2 -1
-2
1 2 3 4 5 6
-6
-8
-10-
The function graphed above is:
Concave up on the interval(s)
Concave down on the interval(s)
There is an inflection point at:
6
5
4
3
2
1
-6 -5
-3 -2
3
-1
-2
-3
-4
-5
The graph above is a transformation of the function x²
Write an equation for the function graphed above
g(x)
=
6
5
4
3
2
1
-1
-1
-2
-3
-4
A
-5
-6-
The graph above shows the function f(x). The graph below shows g(x).
6
5
4
3
2
1
3
-1
-2
-3
-4
-5
-6 |
g(x) is a transformation of f(x) where g(x) = Af(Bx) where:
A =
B =
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