Explanation Given: The volume of water is 352 ml and the density is 1 g / ml . Explanation: The heat required to lower the temperature of water can be calculated as follows: q = m C s Δ T …… (1) Here C s is the specific heat, Δ T is the change in temperature, and m is the mass of water. Calculate the mass of water as follows: m = d V Here, d is the density of water and V is the volume of water. Substitute V as 352 ml and the density as 1 g / ml in the above expression as follows: m = 1 g / ml × 352 ml = 352 g Calculate Δ T as follows: Δ T = 25 ∘ C − 5 ∘ C = 20 ∘ C Substitute m as 352 g , Δ T as 20 ∘ C , and the specific heat capacity of water C s as 4.18 J / g ∘ C in equation (1) as follows: q = ( 352 g ) ( 4

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ISBN: 9780321809247

Author: Nivaldo J. Tro

Publisher: Prentice Hall

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Chapter 11, Problem 82E

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To determine: Grams of ice require to melt to lower the temperature of water from 25∘C to 5∘C.

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Chapter 11, Problem 81E

Chapter 11, Problem 83E

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Chapter 11 Solutions

Chemistry: A Molecular Approach

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Grams of ice require to melt to lower the temperature of water from 25 ∘ C to 5 ∘ C .

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To determine: Grams of ice require to melt to lower the temperature of water from 25∘C to 5∘C.

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Chapter 11 Solutions