(a) Explanation Given info: The mass of the person is 67.0 kg , the distance between the two pillars is 1.10 m and the force exerted by the pillar at point A is 828 N . The free body diagram of lightweight diving board supported by two pillars is shown below. Figure (1) In the above figure, point A shows the first pillar at the end of the board and point B shows the second pillar which is at a distance of d from pillar at point A . Under the equilibrium condition, the net torque about point A is zero. Write the equilibrium equation of torque about point A . ∑ τ = 0 ( F 1 × d ) − ( m g × ( L − d ) ) = 0 Here, F 1 is the force in downward direction exerted by the first pillar which is at point A . d is the distance between two pillars. L is the distance of the person from the pillar at point A . m is the mass of the person. g is the acceleration due to gravity. Substitute 828 N for F 1 , 1 (b) To determine The force exerted by the second pillar.

5th Edition

ISBN: 9780321976444

Author: James S. Walker

Publisher: PEARSON

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Center of Gravity of a system

The centre of gravity is a property that is based on the geometry of a rigid body or any particle. It is described as an equilibrium point or a hypothetical location where the total weight of the body is concentrated.

Question

Chapter 11, Problem 81GP

(a)

To determine

The distance of the person from the pillar at point A .

(b)

To determine

The force exerted by the second pillar.

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Chapter 11, Problem 80GP

Chapter 11, Problem 82GP

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The distance of the person from the pillar at point A .

Solution Summary: The free body diagram of lightweight diving board supported by two pillars is shown below.

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The distance of the person from the pillar at point A .

The force exerted by the second pillar.

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Chapter 11 Solutions