Explanation Given info: The length of the basket is 62 cm , the mass of the milk carton is 1.81 kg , the mass of the cereal box is 0.722 kg and the mass of the orange juice container is 1.8 kg . The free body diagram of the milk carton, cereal box and orange juice container is shown below. Figure (1) Apply Newton's second law of motion for torque at O . ∑ τ = 0 m orange juice g x + m cereal g × ( 31 cm ) − m milk g × ( 31 cm ) = 0 Here, m orange juice is the mass of orange juice. g is the acceleration due to gravity. x is the distance between the orange juice and centre point O . m cereal is the mass of cereal. m milk is the mass of the milk. Substitute 1.81 kg for m milk , 0.722 kg for m cereal , 1.8 kg for m orange juice and 9.81 m / s 2 for g in above equation. [ ( 1.8 kg × x + 0.722 kg × 31 cm × 1 m 100 cm − 1.81 kg × 31 cm × 1 m 100 cm ) ( 9

5th Edition

ISBN: 9780321976444

Author: James S. Walker

Publisher: PEARSON

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Chapter 11, Problem 35PCE

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The location where the container of orange juice should be placed so that the basket balances at its center.

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Chapter 11, Problem 34PCE

Chapter 11, Problem 36PCE

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The location where the container of orange juice should be placed so that the basket balances at its center.

Solution Summary: The author determines the location where the container of orange juice should be placed so that the basket balances at its center.

The location where the container of orange juice should be placed so that the basket balances at its center.

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Chapter 11 Solutions