EBK ESSENTIALS OF MIS,
13th Edition
ISBN: 8220106778494
Author: LAUDON
Publisher: PEARSON
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Chapter 11, Problem 7DQ
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Intelligence of Intelligent technique:
Intelligent technique is used in business which includes intelligent agents, natural language processing (NLP), machine learning, computer vision systems, genetic
- This technique helps the decision makers by getting individual and combined information, learning outlines and performances in very huge amounts of data, executing some human interest activities, and producing answers to problems which very difficult for humans to crack on their own...
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1. Enabled with SSL, HTTPS protocol is widely used to provide secure Web services to Web users using Web browsers on the Internet. How is a secure communication channel established at the start of communication between a Web server running HTTPS and a Web browser?
Consider the following threats to Web security and how each of these threats is countered by a particular feature of SSL.
Man-in-the-middle attack: An attacker interposes during key exchange, acting as the client to the server and as the server to the client.
Password sniffing: Passwords in HTTP or other application traffic are “eavesdropped.”
SYN flooding: An attacker sends TCP SYN messages to request a connection but does not respond to the final message to establish the connection fully. The attacked TCP module typically leaves the “half-open” connection around for a few minutes. Repeated SYN messages can clog the TCP module.
SQL Injection on UPDATE Statement for educational purpose only
Based on the information below how do i update this code in order to update the emplyees field, eg admin nickname, email,address, phone number etc?
' ; UPDATE users SET NickName='Hacked' WHERE role='admin' --
If a SQL injection vulnerability happens to an UPDATE statement, the damage will be more severe, because attackers can use the vulnerability to modify databases. In our Employee Management application, there is an Edit Profile page (Figure 2) that allows employees to update their profile information, including nickname, email, address, phone number, and password. To go to this page, employees need to log in first.
When employees update their information through the Edit Profile page, the following SQL UPDATE query will be executed. The PHP code implemented in unsafe edit backend.php file is used to update employee’s profile information. The PHP file is located in the /var/www/SQLInjection directory.
Chapter 11 Solutions
EBK ESSENTIALS OF MIS,
Ch. 11.3 - Prob. 1CQ1Ch. 11.3 - Prob. 2CQ1Ch. 11.3 - Prob. 3CQ1Ch. 11.3 - Prob. 1CQ2Ch. 11.3 - Prob. 2CQ2Ch. 11.3 - Prob. 3CQ2Ch. 11 - Prob. 1IQCh. 11 - Prob. 2IQCh. 11 - Prob. 4IQCh. 11 - Prob. 5IQ
Ch. 11 - Prob. 1RQCh. 11 - Prob. 2RQCh. 11 - Prob. 3RQCh. 11 - Prob. 4RQCh. 11 - Prob. 5DQCh. 11 - Prob. 6DQCh. 11 - Prob. 7DQCh. 11 - Prob. 9HMPCh. 11 - Prob. 11HMPCh. 11 - Prob. 12CTPCh. 11 - Prob. 13CSQCh. 11 - Prob. 14CSQCh. 11 - Prob. 15CSQCh. 11 - Prob. 16CSQCh. 11 - Prob. 17CSQCh. 11 - Prob. 18MLMCh. 11 - Prob. 19MLM
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- 4. Suppose we have a perfect binary tree with height h 0 representing a heap, meaning it = has n 2+1 1 keys indexed from 1 to 2+1 1. When we run convertomaxheap we run maxheapify in reverse order on every key with children. Let's examine the worst-case - In the worst-case every single key gets swapped all the way to the leaf level. (a) For each level in the tree there are a certain number of nodes and each of those nodes [10 pts] requires a certain number of swaps. Fill in the appropriate values/expressions in the table: Level Number of Keys Number of Swaps per Key 0 2 .. (b) Write down a sum for the total number of swaps required. This should involve h, not n. [10 pts] Totalarrow_forwardThe next problem concerns the following C code: /copy input string x to buf */ void foo (char *x) { char buf [8]; strcpy((char *) buf, x); } void callfoo() { } foo("ZYXWVUTSRQPONMLKJIHGFEDCBA"); Here is the corresponding machine code on a Linux/x86 machine: 0000000000400530 : 400530: 48 83 ec 18 sub $0x18,%rsp 400534: 48 89 fe mov %rdi, %rsi 400537: 48 89 e7 mov %rsp,%rdi 40053a: e8 di fe ff ff callq 400410 40053f: 48 83 c4 18 add $0x18,%rsp 400543: c3 retq 400544: 0000000000400544 : 48 83 ec 08 sub $0x8,%rsp 400548: bf 00 06 40 00 mov $0x400600,%edi 40054d: e8 de ff ff ff callq 400530 400552: 48 83 c4 08 add $0x8,%rsp 400556: c3 This problem tests your understanding of the program stack. Here are some notes to help you work the problem: ⚫ strcpy(char *dst, char *src) copies the string at address src (including the terminating '\0' character) to address dst. It does not check the size of the destination buffer. • You will need to know the hex values of the following characters:arrow_forward1234 3. Which line prevents compiler optimization? Circle one: 1234 Suggested solution: Store strlen(str) in a variable before the if statement. ⚫ Remove the if statement. Replace index 0 && index < strlen(str)) { 5 } } = str [index] = val;arrow_forward
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