
Concept explainers
(a)
Interpretation:
The hybridization of atomic orbitals should be described briefly.
Concept introduction:
When there is a formation of a new set of orbitals by overlapping of valence shell atomic orbitals, it is called as hybridization and the orbitals are known as hybridized orbitals.
These newly formed hybridized orbitals are present in equal number to the
(b)
Interpretation:
The
Concept introduction:
Hybridization resulted due to the formation of a new set of orbitals by overlapping of valence shell atomic orbitals and the orbitals are known as hybridized orbitals.
When hybridized orbitals are again overlapped with other hybridized orbitals or valence shell orbitals through the inter-nuclear axis, it is known as a sigma bond.
(c)
Interpretation:
The Kekule structure of benzene should be explained.
Concept introduction:
Kekule was the first scientist who had given the first stable structure of benzene in which six carbons of benzene are present in a hexagonal shape.
In this structure, each carbon contains one hydrogen atom with it and single and double bonds are present in between carbon-carbon atoms.
(d)
Interpretation:
Theband theory should be explained for metallic bonding.
Concept introduction:
Metallic bonding is a term used to represent the
This type of bonding is the strongest bonding as metals have strong attraction forces between them.

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Chapter 11 Solutions
General Chemistry: Principles and Modern Applications, Loose Leaf Version (11th Edition)
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- CHEMICAL KINETICS. Indicate the approximation methods for solving the rate equation.arrow_forwardTRANSMITTANCE เบบ Please identify the one structure below that is consistent with the 'H NMR and IR spectra shown and draw its complete structure in the box below with the protons alphabetically labeled as shown in the NMR spectrum and label the IR bands, including sp³C-H and sp2C-H stretch, indicated by the arrows. D 4000 OH LOH H₂C CH3 OH H₂C OCH3 CH3 OH 3000 2000 1500 HAVENUMBERI-11 1000 LOCH3 Draw your structure below and label its equivalent protons according to the peak labeling that is used in the NMR spectrum in order to assign the peaks. Integrals indicate number of equivalent protons. Splitting patterns are: s=singlet, d=doublet, m-multiplet 8 3Hb s m 1Hd s 3Hf m 2Hcd 2Had 1He 鄙视 m 7 7 6 5 4 3 22 500 T 1 0arrow_forwardRelative Transmittance 0.995 0.99 0.985 0.98 Please draw the structure that is consistent with all the spectral data below in the box and alphabetically label the equivalent protons in the structure (Ha, Hb, Hc ....) in order to assign all the proton NMR peaks. Label the absorption bands in the IR spectrum indicated by the arrows. INFRARED SPECTRUM 1 0.975 3000 2000 Wavenumber (cm-1) 1000 Structure with assigned H peaks 1 3 180 160 140 120 100 f1 (ppm) 80 60 40 20 0 C-13 NMR note that there are 4 peaks between 120-140ppm Integral values equal the number of equivalent protons 10.0 9.0 8.0 7.0 6.0 5.0 4.0 3.0 2.0 1.0 0.0 fl (ppm)arrow_forward
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