Chapter 11, Problem 51P

с. d. СнЗ Сизена=-4=4 Cla H Eget3 над f. e. H-C=C-CH3 + 285 → H-C=C-CH3+2не H-C=C-CH3 + Nanta» g+ CH₂ CH₂-G = G-C₁₂-G=CH₂ + 2HI→ H H H AL

The IR (infrared) spectra of two pure compounds (0.010 M compound A in solvent and 0.010 M compound B in solvent) are given. The pathlength of the cell is 1.00 cm. The y-axis in the spectra is transmittance rather than absorption, so that the wavenumbers at which there is a dip in the curve correspond to absorption peaks. A mixture of A and B in unknown concentrations gave a percent transmittance of 49.8% at 2976 cm¹ and 44.9% at 3030 cm-1 Wavenumber 0.010 M A 0.010 M B Unknown 3030 cm-1 35.0% 93.0% 44.9% 2976 cm-¹ 76.0% 42.0% 49.8% What are the concentrations of A and B in the unknown sample? Transmittance (%) 100 90 80 70 60 50 40 2976 cm-1 30 3030 cm-1 20 Pure A 10 Pure B 0 3040 2990 Wavenumber (cm-1) 2940 2890

synthesize 1-propyne starting with propane.

starting reactant IV target + enantiomer 1) BH3, THF 2) H₂O2, NaOH, H₂O 1) Hg(OAc)2, THF, H₂O (or ROH) 2) NaBH4 D2, Pt/C H₂, Pt/C D2, Lindlar catalyst or Ni₂B H₂, Lindlar catalyst or Ni₂B NaNH, OH/H₂O or SH/H₂S H₂O/H₂O 1) 03 2) H₂O 1) 03 2) (CH3)2S HBr, w/ROOR HBr, (cold, dark, no ROOR) Naº, NH3(e) NBS (trace Br2), light HgSO4, H2SO4, H₂O Naº, ROH 1) Sia₂BH, THF 2) H2O2, NaOH, H₂O H3O/ROH or H₂O*/RSH OR/ROH or SR/RSH 1) OsO4, NMO 2) NaHSO3, H₂O 1) MCPBA (peroxy acid) 2) H3O, H2O (or ROH or RSH) KMnO4 (warm, concentrated) Br₂/H₂O Br₂, heat or light Br2, cold, dark, no peroxides (CH3)3CO(CH3)3COH ROH or RSH H₂O KMnO4/OH (cold, dilute)

None

Indicate whether the ability of atoms to associate with each other depends on electron affinity.

1) Write the reduction half reactions and find the reduction potential for each pair.a. Zn/Zn2+b. Cu/Cu2+c. Al/Al3+d. Ag/Ag1+   2) For each of the following voltaic cells, identify the anode, cathode, write the standard cell notation/diagram, and predict the cell potential.

The following reaction is first order in NO2.  Solve the differential rate equation to create the integrated rate law. NO2 (g) -> NO(g) + O (g)

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