CHEMISTRY IN FOCUS W/ OWL (LL)>IP<
CHEMISTRY IN FOCUS W/ OWL (LL)>IP<
6th Edition
ISBN: 9781337306317
Author: Tro
Publisher: CENGAGE L
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Chapter 11, Problem 51E
Interpretation Introduction

Interpretation:

The pressure of an automobile tire at 70

C, having volume 10.1 L, is to be calculated.

Concept Introduction:

Combined gas law, also called general gas equation, combines Boyle’s Law and Charles’s Law. It states that the ratio of the pressure-volume product and the absolute temperature of a gas is equal to a constant.

P1V1T1=P2V2T2

Here, P1 and P2 are the initial and final pressures of the ideal gas, V1 and V2 are the initial and the final volumes of the gas and T1, T2 are the initial and final temperatures of the ideal gas.

Converting degree Celsius to Kelvin by adding 273K, the conversion factor is as:

T=°C+ 273K

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13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. cleavage Bond A •CH3 + 26.← Cleavage 2°C. + Bond C +3°C• CH3 2C Cleavage E 2°C. 26. weakest bond Intact molecule Strongest 3°C 20. Gund Largest argest a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. C Weakest bond A Produces Most Bond Strongest Bond Strongest Gund produces least stable radicals Weakest Stable radical b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 13°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. • CH3 methyl radical Formed in Gund A Cleavage c.…

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