(a) Explanation Definition used: “The equation of the parabola with vertex V ( 0 , 0 ) , focus F ( 0 , p ) and directrix y = − p is x 2 = 4 p y ”. The equation of the parabola is x 2 = − 8 y . Compare the equation x 2 = − 8 y with the parabola x 2 = 4 p y and obtain, 4 p = ȡ (b) To determine To sketch: The graph of the parabola x 2 = − 8 y with its directrix.

Bundle: College Algebra, 7th + WebAssign Printed Access Card for Stewart/Redlin/Watson's College Algebra, 7th Edition, Single-Term

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ISBN: 9781305618152

Author: Lothar Redlin, Saleem Watson, James Stewart

Publisher: CENGAGE C

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Chapter 11, Problem 4RE

(a)

To determine

To find: The vertex, focus and directrix of the parabola x2=−8y .

(b)

To determine

To sketch: The graph of the parabola x2=−8y with its directrix.

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Chapter 11, Problem 3RE

Chapter 11, Problem 5RE

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Chapter 11 Solutions

Bundle: College Algebra, 7th + WebAssign Printed Access Card for Stewart/Redlin/Watson's College Algebra, 7th Edition, Single-Term

Ch. 11.1 - A parabola is the set of all points in the plane...Ch. 11.1 - The graph of the equation x2 = 4py is a parabola...Ch. 11.1 - The graph of the equation y2 = 4px is a parabola...Ch. 11.1 - Label the focus, directrix, and vertex on the...Ch. 11.1 - Graphs of Parabolas Match the equation with the...Ch. 11.1 - Prob. 6E Ch. 11.1 - Graphs of Parabolas Match the equation with the...Ch. 11.1 - Prob. 8E Ch. 11.1 - Graphs of Parabolas Match the equation with the...Ch. 11.1 - Graphs of Parabolas Match the equation with the...

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The vertex, focus and directrix of the parabola x 2 = − 8 y .

Solution Summary: The author explains the vertex, focus, and directrix of the parabola x2=-8y.