A Small Scale Approach to Organic Laboratory Techniques
4th Edition
ISBN: 9781305799875
Author: Donald L. Pavia; George S. Kriz; Gary M. Lampman
Publisher: Cengage Learning US
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Chapter 11, Problem 4Q
Interpretation Introduction
Interpretation:
The possible explanation for the lower melting point of isolated caffeine than the literature value needs to be given.
Concept Introduction:
In the isolation of caffeine from tea leaves, the main problem is that the caffeine is not the only natural substance present in the tea leaves, but there are other substances as well from which it needs to be separated. The main component is cellulose which is
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9. OA. Rank the expected boiling points of the compounds shown below from highest to lowest. Place your answer
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There is an instrument in Johnson 334 that measures total-reflectance x-ray fluorescence (TXRF) to do elemental analysis (i.e., determine what elements are present in a sample). A researcher is preparing a to measure calcium content in a series of well water samples by TXRF with an internal standard of vanadium (atomic symbol: V). She has prepared a series of standard solutions to ensure a linear instrument response over the expected Ca concentration range of 40-80 ppm. The concentrations of Ca and V (ppm) and the instrument response (peak area, arbitrary units) are shown below. Also included is a sample spectrum. Equation 1 describes the response factor, K, relating the analyte signal (SA) and the standard signal (SIS) to their respective concentrations (CA and CIS).
Ca, ppm
V, ppm
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14261.02
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17997.10
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39275.74
12988.01
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100.0…
A mixture of 0.568 M H₂O, 0.438 M Cl₂O, and 0.710 M HClO are enclosed in a vessel at 25 °C.
H₂O(g) + C₁₂O(g) = 2 HOCl(g)
K = 0.0900 at 25°C
с
Calculate the equilibrium concentrations of each gas at 25 °C.
[H₂O]=
[C₁₂O]=
[HOCI]=
M
Σ
M
Chapter 11 Solutions
A Small Scale Approach to Organic Laboratory Techniques
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