Chapter 11, Problem 41QP

Interpretation Introduction

Interpretation:

The maximum amount of $\text{KCl}$ in grams $\left(\text{g}\right)$ that will dissolve in $\text{50}\text{.0 g}$ of water at $20°\text{C}$ is to be determined.

Concept Introduction:

$\text{KCl}$ is an ionic solute and water is a polar solvent. Thus, $\text{KCl}$ is easily soluble in water to give solution. Solubility of a solute is the maximum amount of the solute in grams $\left(\text{g}\right)$ or kilograms $\left(\text{kg}\right)$ soluble in a given amount of solvent.