In Exercises 37 and 38 , we specify a line by giving the slope and one point on the line. We give the first coordinate of some points on the line. Without deriving the equation of the line, find the second coordinate of each point. Slope is 2 , ( 1 , 3 ) on line; ( 2 , ) ; ( 3 , ) ; ( 0 , ) .
In Exercises 37 and 38 , we specify a line by giving the slope and one point on the line. We give the first coordinate of some points on the line. Without deriving the equation of the line, find the second coordinate of each point. Slope is 2 , ( 1 , 3 ) on line; ( 2 , ) ; ( 3 , ) ; ( 0 , ) .
Solution Summary: The author explains how to calculate the second coordinate of each of the points , whose slope is 2 and passes through the point . Substituting all the above values in the slope formula.
In Exercises
37
and
38
, we specify a line by giving the slope and one point on the line. We give the first coordinate of some points on the line. Without deriving the equation of the line, find the second coordinate of each point.
The correct answer is Ccould you show me how to do it by finding a0 and and akas well as setting up the piecewise function and integrating
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1
7. Fill in the blanks to write the calculus problem that would result in the following integral (do
not evaluate the interval). Draw a graph representing the problem.
So
π/2
2 2πxcosx dx
Find the volume of the solid obtained when the region under the curve
on the interval
is rotated about the
axis.
38,189
5. Draw a detailed graph to and set up, but do not evaluate, an integral for the volume of the
solid obtained by rotating the region bounded by the curve: y = cos²x_for_ |x|
≤
and the curve y
y =
about the line
x =
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Chapter 1 Solutions
MyLab Math with Pearson eText -- 24 Month Access -- for Calculus & Its Applications
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