Explanation Section 1: To determine: The excess internal energy. Solution: The excess internal energy is 837 kJ . Explanation: Given Info : Running time 30 min, rate is 4.00 × 10 2 kcal / h . Formula to calculate excess internal energy in 30 min of run is, Q excess = R t Q excess is the excess internal energy, R is the rate of elimination, t is the time of running, Substitute ( 4.00 × 10 2 kcal / h ) for R and 30 min for t to find Q excess . Q excess = ( 4.00 × 10 2 kcal h ) ( 4186 J 1 kcal ) ( 30 min ) ( 0.016667 hr 1 min ) = 837 kJ Thus, the excess internal energy is 837 kJ . Section 2: To determine: The mass of water that will be evaporated by the excess internal energy. Solution: The mass of water that will be evaporated by the excess internal energy. is 0.33 kg . Explanation: Given Info : Running time 30 min, rate is 4.00 × 10 2 kcal / h , and latent heat of vaporization is 2.5 × 10 6 J / kg Formula to calculate the mass of water that will be evaporated by the excess internal energy is, m evap = Q excess L v m evap is the mass of water evaporated, L v is the latent heat of vaporization of water at room temp, Substitute 837 kJ for Q excess and 2.5 × 10 6 J / kg for L v to find m evap

10th Edition

ISBN: 9781337520379

Author: Vuille

Publisher: YUZU

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Question

Chapter 11, Problem 32P

To determine

The fraction of water provided by fat mechanism.

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The fraction of water provided by fat mechanism.

Solution Summary: The author analyzes the tion of water provided by fat mechanism. The excess internal energy is 837kJ.

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The fraction of water provided by fat mechanism.

Chapter 11 Solutions