Engineering Fundamentals
Engineering Fundamentals
6th Edition
ISBN: 9780357112144
Author: Saeed Moaveni
Publisher: MISC PUBS
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Chapter 11, Problem 24P
To determine

Find the maximum amount of energy released when 10lbm of coal burnt and also find the amount of energy released when 15ft3 of natural gas burnt in Oklahoma.

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1) Heating the water in a 55-gallon water heater requires about 2.0 x 103 kJ of energy.          a) Assume the energy came from natural gas with 80% efficiency; how many grams of natural gas are required?          b) Assume the energy came from electricity with 80% efficiency and that the electricity was produced from the combustion of coal with 30% efficiency; how many grams of coal are required?   For problem above, calculate how much CO2 in grams is emitted to the atmosphere.             For a: Use the balanced equation for the combustion of methane (CH4) to determine how many grams of CO2are produced from the amount of natural gas required.             For b: Assume that coal produces 5.25 kJ of energy per gram of CO2 produced. Calculate how much CO2 in grams is produced.
Calculation of Energy saving  We are given that Average energy use for waste water treatment = 652 KWh for 625,853 gallons Average energy use for 1 gallon waste water treatment = 652625,853 KWh Per day Average energy use for  29.522 Million gallon waste water treatment = 652625,853*29.522*106 Per day Average energy use for  29.522 Million gallon waste water treatment = 30753.29 KWh " Per day  Energy saving = 30753.29 KWh " Finding How to come up with 30753.29KWh? If  652 KWh for 625,853 gallons 652,853*29.522*106 = ??
We have exposed 1 kg of water, 1 kg of brick, and 1 kg of concrete each to a heat source that puts out 100 J every second. Assuming that all of the supplied energy goes to each material and they were all initially at the same temperature, which one of these materials will have a greater temperature rise after 10 s? We can answer this question using Equation as shown . We will first look up the values of the specific heat for water, brick, and concrete, which are cwater = 4180 J⁄kg K, cbrick = 960 J⁄kg K and cconcrete = 880 J⁄kg K . Now applying as shown , Ethermal = mc(Tfinal Tinitial) to each situation, it should be clear that although each material has the same amount of mass and is exposed to the same amount of thermal energy, the concrete will experience a higher temperature rise because it has the lowest heat capacity value among the three given materials.

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Engineering Fundamentals

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