Biostatistics for the Biological and Health Sciences
Biostatistics for the Biological and Health Sciences
2nd Edition
ISBN: 9780134679235
Author: Triola
Publisher: PEARSON
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Chapter 1.1, Problem 22SLCT
To determine

To explain what issue can be addressed by conducting a statistical analysis of the measurements.

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Show that L′(θ) = Cθ394(1 −2θ)604(395 −2000θ).
a) Let X and Y be independent random variables both with the same mean µ=0. Define a new random variable W = aX +bY, where a and b are constants. (i) Obtain an expression for E(W).
The table below shows the estimated effects for a logistic regression model with squamous cell esophageal cancer (Y = 1, yes; Y = 0, no) as the response. Smoking status (S) equals 1 for at least one pack per day and 0 otherwise, alcohol consumption (A) equals the average number of alcohoic drinks consumed per day, and race (R) equals 1 for blacks and 0 for whites. Variable Effect (β) P-value Intercept -7.00 <0.01 Alcohol use 0.10 0.03 Smoking 1.20 <0.01 Race 0.30 0.02 Race × smoking 0.20 0.04 Write-out the prediction equation (i.e., the logistic regression model) when R = 0 and again when R = 1. Find the fitted Y S conditional odds ratio in each case.  Next, write-out the logistic regression model when S = 0 and again when S = 1. Find the fitted Y R conditional odds ratio in each case.

Chapter 1 Solutions

Biostatistics for the Biological and Health Sciences

Ch. 1.1 - Prob. 11SLCTCh. 1.1 - Prob. 12SLCTCh. 1.1 - Prob. 13SLCTCh. 1.1 - Prob. 14SLCTCh. 1.1 - Prob. 15SLCTCh. 1.1 - Prob. 16SLCTCh. 1.1 - Prob. 17SLCTCh. 1.1 - Prob. 18SLCTCh. 1.1 - Prob. 19SLCTCh. 1.1 - Prob. 20SLCTCh. 1.1 - Prob. 21SLCTCh. 1.1 - Prob. 22SLCTCh. 1.1 - Prob. 23SLCTCh. 1.1 - Prob. 24SLCTCh. 1.1 - Prob. 25SLCTCh. 1.1 - Prob. 26SLCTCh. 1.1 - Prob. 27SLCTCh. 1.1 - Prob. 28SLCTCh. 1.1 - Prob. 29SLCTCh. 1.1 - Prob. 30SLCTCh. 1.1 - Prob. 31SLCTCh. 1.1 - Prob. 32SLCTCh. 1.2 - Prob. 1SLCTCh. 1.2 - Prob. 2SLCTCh. 1.2 - Prob. 3SLCTCh. 1.2 - Prob. 4SLCTCh. 1.2 - Prob. 5SLCTCh. 1.2 - Prob. 6SLCTCh. 1.2 - Prob. 7SLCTCh. 1.2 - Prob. 8SLCTCh. 1.2 - Prob. 9SLCTCh. 1.2 - Prob. 10SLCTCh. 1.2 - Prob. 11SLCTCh. 1.2 - Prob. 12SLCTCh. 1.2 - Prob. 13SLCTCh. 1.2 - Prob. 14SLCTCh. 1.2 - Prob. 15SLCTCh. 1.2 - Prob. 16SLCTCh. 1.2 - Prob. 17SLCTCh. 1.2 - Prob. 18SLCTCh. 1.2 - Prob. 19SLCTCh. 1.2 - Prob. 20SLCTCh. 1.2 - Prob. 21SLCTCh. 1.2 - Prob. 22SLCTCh. 1.2 - Prob. 23SLCTCh. 1.2 - Prob. 24SLCTCh. 1.2 - Prob. 25SLCTCh. 1.2 - Prob. 26SLCTCh. 1.2 - Prob. 27SLCTCh. 1.2 - Prob. 28SLCTCh. 1.2 - Prob. 29SLCTCh. 1.2 - Prob. 30SLCTCh. 1.2 - Prob. 31SLCTCh. 1.2 - Prob. 32SLCTCh. 1.2 - Prob. 33SLCTCh. 1.3 - Prob. 1SLCTCh. 1.3 - Prob. 2SLCTCh. 1.3 - Prob. 3SLCTCh. 1.3 - Prob. 4SLCTCh. 1.3 - Prob. 5SLCTCh. 1.3 - Prob. 6SLCTCh. 1.3 - Prob. 7SLCTCh. 1.3 - Prob. 8SLCTCh. 1.3 - Prob. 9SLCTCh. 1.3 - Prob. 10SLCTCh. 1.3 - Prob. 11SLCTCh. 1.3 - Prob. 12SLCTCh. 1.3 - Prob. 13SLCTCh. 1.3 - Prob. 14SLCTCh. 1.3 - Prob. 15SLCTCh. 1.3 - Prob. 16SLCTCh. 1.3 - Prob. 17SLCTCh. 1.3 - Prob. 18SLCTCh. 1.3 - Prob. 19SLCTCh. 1.3 - Prob. 20SLCTCh. 1.3 - Prob. 21SLCTCh. 1.3 - Prob. 22SLCTCh. 1.3 - Prob. 23SLCTCh. 1.3 - Prob. 24SLCTCh. 1.3 - Prob. 25SLCTCh. 1.3 - Prob. 26SLCTCh. 1.3 - Prob. 27SLCTCh. 1.3 - Prob. 28SLCTCh. 1.3 - Prob. 29SLCTCh. 1.3 - Prob. 30SLCTCh. 1.3 - Prob. 31SLCTCh. 1.3 - Prob. 32SLCTCh. 1.3 - Prob. 33SLCTCh. 1.3 - Prob. 34SLCTCh. 1.3 - Prob. 35SLCTCh. 1.3 - Prob. 36SLCTCh. 1.3 - Prob. 37SLCTCh. 1.3 - Prob. 38SLCTCh. 1 - Prob. 1CQQCh. 1 - Prob. 2CQQCh. 1 - Prob. 3CQQCh. 1 - Prob. 4CQQCh. 1 - Prob. 5CQQCh. 1 - Prob. 6CQQCh. 1 - Prob. 7CQQCh. 1 - Prob. 8CQQCh. 1 - Prob. 9CQQCh. 1 - Prob. 10CQQCh. 1 - Prob. 1RECh. 1 - Prob. 2RECh. 1 - Prob. 3RECh. 1 - Prob. 4RECh. 1 - Prob. 5RECh. 1 - Prob. 6RECh. 1 - Prob. 7RECh. 1 - Prob. 8RECh. 1 - Prob. 9RECh. 1 - Prob. 10RECh. 1 - Prob. 1CRECh. 1 - Prob. 2CRECh. 1 - Prob. 3CRECh. 1 - Prob. 4CRECh. 1 - Prob. 5CRECh. 1 - Prob. 6CRECh. 1 - Prob. 7CRECh. 1 - Prob. 8CRECh. 1 - Prob. 9CRECh. 1 - Prob. 10CRECh. 1 - Prob. 11CRECh. 1 - Prob. 12CRE
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