Biostatistics for the Biological and Health Sciences
2nd Edition
ISBN: 9780134679235
Author: Triola
Publisher: PEARSON
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Chapter 1, Problem 1CQQ
To determine
To explain: Whether calculation of
Expert Solution & Answer
Answer to Problem 1CQQ
No, it does not make sense.
Explanation of Solution
Given:
Various codes have been assigned codes: 1, 2, 3, 5, 6, 9, 11, 13, 16, 20, 22, 26, 32 and 40.
The provided data set is nominal due to assigning of code to the data set. It must be noted that it is not possible to compute the mean for the provided data set because it is a nominal data. Thus, it does not have any significance.
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How many apps? According to a website, the mean number of apps on a smartphone in the United States is 82. Assume
the number of apps is normally distributed with mean 82 and standard deviation 30.
Part 1 of 2
(a) What proportion of phones have more than 47 apps? Round the answer to four decimal places.
The proportion of phones that have more than 47 apps is 0.8783
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You are provided with data that includes all 50 states of the United States. Your task is to draw a sample of:
20 States using Random Sampling (2 points: 1 for random number generation; 1 for random sample)
10 States using Systematic Sampling (4 points: 1 for random numbers generation; 1 for generating random sample different from the previous answer; 1 for correct K value calculation table; 1 for correct sample drawn by using systematic sampling) (For systematic sampling, do not use the original data directly. Instead, first randomize the data, and then use the randomized dataset to draw your sample. Furthermore, do not use the random list previously generated, instead, generate a new random sample for this part. For more details, please see the snapshot provided at the end.) You are provided with data that includes all 50 states of the United States. Your task is to draw a sample of: o 20 States using Random Sampling (2 points: 1 for random number generation; 1 for random sample) o…
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Listed in the accompanying table are weights (kg) of randomly selected U.S. Army male personnel measured in 1988 (from "ANSUR I 1988") and different weights (kg) of randomly selected U.S.
Army male personnel measured in 2012 (from "ANSUR II 2012"). Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not
assume that the population standard deviations are equal. Complete parts (a) and (b).
Click the icon to view the ANSUR data.
a. Use a 0.05 significance level to test the claim that the mean weight of the 1988…
Chapter 1 Solutions
Biostatistics for the Biological and Health Sciences
Ch. 1.1 - Prob. 1SLCTCh. 1.1 - Prob. 2SLCTCh. 1.1 - Prob. 3SLCTCh. 1.1 - Prob. 4SLCTCh. 1.1 - Prob. 5SLCTCh. 1.1 - Prob. 6SLCTCh. 1.1 - Prob. 7SLCTCh. 1.1 - Prob. 8SLCTCh. 1.1 - Prob. 9SLCTCh. 1.1 - Prob. 10SLCT
Ch. 1.1 - Prob. 11SLCTCh. 1.1 - Prob. 12SLCTCh. 1.1 - Prob. 13SLCTCh. 1.1 - Prob. 14SLCTCh. 1.1 - Prob. 15SLCTCh. 1.1 - Prob. 16SLCTCh. 1.1 - Prob. 17SLCTCh. 1.1 - Prob. 18SLCTCh. 1.1 - Prob. 19SLCTCh. 1.1 - Prob. 20SLCTCh. 1.1 - Prob. 21SLCTCh. 1.1 - Prob. 22SLCTCh. 1.1 - Prob. 23SLCTCh. 1.1 - Prob. 24SLCTCh. 1.1 - Prob. 25SLCTCh. 1.1 - Prob. 26SLCTCh. 1.1 - Prob. 27SLCTCh. 1.1 - Prob. 28SLCTCh. 1.1 - Prob. 29SLCTCh. 1.1 - Prob. 30SLCTCh. 1.1 - Prob. 31SLCTCh. 1.1 - Prob. 32SLCTCh. 1.2 - Prob. 1SLCTCh. 1.2 - Prob. 2SLCTCh. 1.2 - Prob. 3SLCTCh. 1.2 - Prob. 4SLCTCh. 1.2 - Prob. 5SLCTCh. 1.2 - Prob. 6SLCTCh. 1.2 - Prob. 7SLCTCh. 1.2 - Prob. 8SLCTCh. 1.2 - Prob. 9SLCTCh. 1.2 - Prob. 10SLCTCh. 1.2 - Prob. 11SLCTCh. 1.2 - Prob. 12SLCTCh. 1.2 - Prob. 13SLCTCh. 1.2 - Prob. 14SLCTCh. 1.2 - Prob. 15SLCTCh. 1.2 - Prob. 16SLCTCh. 1.2 - Prob. 17SLCTCh. 1.2 - Prob. 18SLCTCh. 1.2 - Prob. 19SLCTCh. 1.2 - Prob. 20SLCTCh. 1.2 - Prob. 21SLCTCh. 1.2 - Prob. 22SLCTCh. 1.2 - Prob. 23SLCTCh. 1.2 - Prob. 24SLCTCh. 1.2 - Prob. 25SLCTCh. 1.2 - Prob. 26SLCTCh. 1.2 - Prob. 27SLCTCh. 1.2 - Prob. 28SLCTCh. 1.2 - Prob. 29SLCTCh. 1.2 - Prob. 30SLCTCh. 1.2 - Prob. 31SLCTCh. 1.2 - Prob. 32SLCTCh. 1.2 - Prob. 33SLCTCh. 1.3 - Prob. 1SLCTCh. 1.3 - Prob. 2SLCTCh. 1.3 - Prob. 3SLCTCh. 1.3 - Prob. 4SLCTCh. 1.3 - Prob. 5SLCTCh. 1.3 - Prob. 6SLCTCh. 1.3 - Prob. 7SLCTCh. 1.3 - Prob. 8SLCTCh. 1.3 - Prob. 9SLCTCh. 1.3 - Prob. 10SLCTCh. 1.3 - Prob. 11SLCTCh. 1.3 - Prob. 12SLCTCh. 1.3 - Prob. 13SLCTCh. 1.3 - Prob. 14SLCTCh. 1.3 - Prob. 15SLCTCh. 1.3 - Prob. 16SLCTCh. 1.3 - Prob. 17SLCTCh. 1.3 - Prob. 18SLCTCh. 1.3 - Prob. 19SLCTCh. 1.3 - Prob. 20SLCTCh. 1.3 - Prob. 21SLCTCh. 1.3 - Prob. 22SLCTCh. 1.3 - Prob. 23SLCTCh. 1.3 - Prob. 24SLCTCh. 1.3 - Prob. 25SLCTCh. 1.3 - Prob. 26SLCTCh. 1.3 - Prob. 27SLCTCh. 1.3 - Prob. 28SLCTCh. 1.3 - Prob. 29SLCTCh. 1.3 - Prob. 30SLCTCh. 1.3 - Prob. 31SLCTCh. 1.3 - Prob. 32SLCTCh. 1.3 - Prob. 33SLCTCh. 1.3 - Prob. 34SLCTCh. 1.3 - Prob. 35SLCTCh. 1.3 - Prob. 36SLCTCh. 1.3 - Prob. 37SLCTCh. 1.3 - Prob. 38SLCTCh. 1 - Prob. 1CQQCh. 1 - Prob. 2CQQCh. 1 - Prob. 3CQQCh. 1 - Prob. 4CQQCh. 1 - Prob. 5CQQCh. 1 - Prob. 6CQQCh. 1 - Prob. 7CQQCh. 1 - Prob. 8CQQCh. 1 - Prob. 9CQQCh. 1 - Prob. 10CQQCh. 1 - Prob. 1RECh. 1 - Prob. 2RECh. 1 - Prob. 3RECh. 1 - Prob. 4RECh. 1 - Prob. 5RECh. 1 - Prob. 6RECh. 1 - Prob. 7RECh. 1 - Prob. 8RECh. 1 - Prob. 9RECh. 1 - Prob. 10RECh. 1 - Prob. 1CRECh. 1 - Prob. 2CRECh. 1 - Prob. 3CRECh. 1 - Prob. 4CRECh. 1 - Prob. 5CRECh. 1 - Prob. 6CRECh. 1 - Prob. 7CRECh. 1 - Prob. 8CRECh. 1 - Prob. 9CRECh. 1 - Prob. 10CRECh. 1 - Prob. 11CRECh. 1 - Prob. 12CRE
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