The possibility of an offspring having both recessive traits when a plant with RrTT is crossed with a plant with rrTt . Red fruit (R) and tall (T) traits are dominant over recessive traits of yellow fruit (r) and short height (t) of plants. Introduction: The dihybrid cross is the cross between the two organisms that carry the same allele for two different traits. The Mendel gave the relationship between the dominant and recessive gene from this concept. The law of independent assortment explains that if the parents are carrying heterozygous alleles for two triats, dominant trait will mask the recessive trait in the F 1 generation. Pictorial representation: Figure 1: The dihybrid cross between RrTT × rrTt Fig. 1: The dihybrid cross between RrTT × rrTt

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Answer 1

Question

Chapter 11, Problem 1TC

Summary Introduction

To determine:

The possibility of an offspring having both recessive traits when a plant with $RrTT$ is crossed with a plant with $rrTt$ . Red fruit (R) and tall (T) traits are dominant over recessive traits of yellow fruit (r) and short height (t) of plants.

Introduction:

The dihybrid cross is the cross between the two organisms that carry the same allele for two different traits. The Mendel gave the relationship between the dominant and recessive gene from this concept. The law of independent assortment explains that if the parents are carrying heterozygous alleles for two triats, dominant trait will mask the recessive trait in the $F_{1}$ generation.

Pictorial representation: Figure 1: The dihybrid cross between $RrTT \times rrTt$

Fig. 1: The dihybrid cross between $RrTT \times rrTt$

Expert Solution & Answer

Explanation of Solution

In a dihybrid cross, the dominant trait needs at least one form of the allele for its expression and recessive trait needs both alleles for its expression. The phenotypic ratio of dihybrid cross is $9: 3: 3: 1$ .

The cross between parental traits did not produce any offspring with both recessive traits (rrtt) and thus the possibility of an offspring having both recessive traits when a plant with $RrTT$ is crossed with a plant with $rrTt$ is zero.

Conclusion

From the punnett square it is clear that the chances of getting an offspring having both recessive trait is none when the parents of $RrTT$ and $rrTt$ genotypes are crossed.

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Answer 2

Question

Chapter 11, Problem 1TC

Summary Introduction

To determine:

The possibility of an offspring having both recessive traits when a plant with $RrTT$ is crossed with a plant with $rrTt$ . Red fruit (R) and tall (T) traits are dominant over recessive traits of yellow fruit (r) and short height (t) of plants.

Introduction:

The dihybrid cross is the cross between the two organisms that carry the same allele for two different traits. The Mendel gave the relationship between the dominant and recessive gene from this concept. The law of independent assortment explains that if the parents are carrying heterozygous alleles for two triats, dominant trait will mask the recessive trait in the $F_{1}$ generation.

Pictorial representation: Figure 1: The dihybrid cross between $RrTT \times rrTt$

Fig. 1: The dihybrid cross between $RrTT \times rrTt$

Expert Solution & Answer

Explanation of Solution

In a dihybrid cross, the dominant trait needs at least one form of the allele for its expression and recessive trait needs both alleles for its expression. The phenotypic ratio of dihybrid cross is $9: 3: 3: 1$ .

The cross between parental traits did not produce any offspring with both recessive traits (rrtt) and thus the possibility of an offspring having both recessive traits when a plant with $RrTT$ is crossed with a plant with $rrTt$ is zero.

Conclusion

From the punnett square it is clear that the chances of getting an offspring having both recessive trait is none when the parents of $RrTT$ and $rrTt$ genotypes are crossed.

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Answer 3

Question

Chapter 11, Problem 1TC

Summary Introduction

To determine:

The possibility of an offspring having both recessive traits when a plant with $RrTT$ is crossed with a plant with $rrTt$ . Red fruit (R) and tall (T) traits are dominant over recessive traits of yellow fruit (r) and short height (t) of plants.

Introduction:

The dihybrid cross is the cross between the two organisms that carry the same allele for two different traits. The Mendel gave the relationship between the dominant and recessive gene from this concept. The law of independent assortment explains that if the parents are carrying heterozygous alleles for two triats, dominant trait will mask the recessive trait in the $F_{1}$ generation.

Pictorial representation: Figure 1: The dihybrid cross between $RrTT \times rrTt$

Fig. 1: The dihybrid cross between $RrTT \times rrTt$

Expert Solution & Answer

Explanation of Solution

In a dihybrid cross, the dominant trait needs at least one form of the allele for its expression and recessive trait needs both alleles for its expression. The phenotypic ratio of dihybrid cross is $9: 3: 3: 1$ .

The cross between parental traits did not produce any offspring with both recessive traits (rrtt) and thus the possibility of an offspring having both recessive traits when a plant with $RrTT$ is crossed with a plant with $rrTt$ is zero.

Conclusion

From the punnett square it is clear that the chances of getting an offspring having both recessive trait is none when the parents of $RrTT$ and $rrTt$ genotypes are crossed.

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Answer 4

Question

Chapter 11, Problem 1TC

Summary Introduction

To determine:

The possibility of an offspring having both recessive traits when a plant with $RrTT$ is crossed with a plant with $rrTt$ . Red fruit (R) and tall (T) traits are dominant over recessive traits of yellow fruit (r) and short height (t) of plants.

Introduction:

The dihybrid cross is the cross between the two organisms that carry the same allele for two different traits. The Mendel gave the relationship between the dominant and recessive gene from this concept. The law of independent assortment explains that if the parents are carrying heterozygous alleles for two triats, dominant trait will mask the recessive trait in the $F_{1}$ generation.

Pictorial representation: Figure 1: The dihybrid cross between $RrTT \times rrTt$

Fig. 1: The dihybrid cross between $RrTT \times rrTt$

Expert Solution & Answer

Explanation of Solution

In a dihybrid cross, the dominant trait needs at least one form of the allele for its expression and recessive trait needs both alleles for its expression. The phenotypic ratio of dihybrid cross is $9: 3: 3: 1$ .

The cross between parental traits did not produce any offspring with both recessive traits (rrtt) and thus the possibility of an offspring having both recessive traits when a plant with $RrTT$ is crossed with a plant with $rrTt$ is zero.

Conclusion

From the punnett square it is clear that the chances of getting an offspring having both recessive trait is none when the parents of $RrTT$ and $rrTt$ genotypes are crossed.

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Answer 5

Chapter 11, Problem 1TC

Summary Introduction

To determine:

The possibility of an offspring having both recessive traits when a plant with $RrTT$ is crossed with a plant with $rrTt$ . Red fruit (R) and tall (T) traits are dominant over recessive traits of yellow fruit (r) and short height (t) of plants.

Introduction:

The dihybrid cross is the cross between the two organisms that carry the same allele for two different traits. The Mendel gave the relationship between the dominant and recessive gene from this concept. The law of independent assortment explains that if the parents are carrying heterozygous alleles for two triats, dominant trait will mask the recessive trait in the $F_{1}$ generation.

Pictorial representation: Figure 1: The dihybrid cross between $RrTT \times rrTt$

Fig. 1: The dihybrid cross between $RrTT \times rrTt$

Expert Solution & Answer

Explanation of Solution

In a dihybrid cross, the dominant trait needs at least one form of the allele for its expression and recessive trait needs both alleles for its expression. The phenotypic ratio of dihybrid cross is $9: 3: 3: 1$ .

The cross between parental traits did not produce any offspring with both recessive traits (rrtt) and thus the possibility of an offspring having both recessive traits when a plant with $RrTT$ is crossed with a plant with $rrTt$ is zero.

Conclusion

From the punnett square it is clear that the chances of getting an offspring having both recessive trait is none when the parents of $RrTT$ and $rrTt$ genotypes are crossed.

Answer 6

Chapter 11, Problem 1TC

Summary Introduction

To determine:

The possibility of an offspring having both recessive traits when a plant with $RrTT$ is crossed with a plant with $rrTt$ . Red fruit (R) and tall (T) traits are dominant over recessive traits of yellow fruit (r) and short height (t) of plants.

Introduction:

The dihybrid cross is the cross between the two organisms that carry the same allele for two different traits. The Mendel gave the relationship between the dominant and recessive gene from this concept. The law of independent assortment explains that if the parents are carrying heterozygous alleles for two triats, dominant trait will mask the recessive trait in the $F_{1}$ generation.

Pictorial representation: Figure 1: The dihybrid cross between $RrTT \times rrTt$

Fig. 1: The dihybrid cross between $RrTT \times rrTt$

Expert Solution & Answer

Explanation of Solution

In a dihybrid cross, the dominant trait needs at least one form of the allele for its expression and recessive trait needs both alleles for its expression. The phenotypic ratio of dihybrid cross is $9: 3: 3: 1$ .

The cross between parental traits did not produce any offspring with both recessive traits (rrtt) and thus the possibility of an offspring having both recessive traits when a plant with $RrTT$ is crossed with a plant with $rrTt$ is zero.

Conclusion

From the punnett square it is clear that the chances of getting an offspring having both recessive trait is none when the parents of $RrTT$ and $rrTt$ genotypes are crossed.

Answer 7

Chapter 11, Problem 1TC

Summary Introduction

To determine:

The possibility of an offspring having both recessive traits when a plant with $RrTT$ is crossed with a plant with $rrTt$ . Red fruit (R) and tall (T) traits are dominant over recessive traits of yellow fruit (r) and short height (t) of plants.

Introduction:

The dihybrid cross is the cross between the two organisms that carry the same allele for two different traits. The Mendel gave the relationship between the dominant and recessive gene from this concept. The law of independent assortment explains that if the parents are carrying heterozygous alleles for two triats, dominant trait will mask the recessive trait in the $F_{1}$ generation.

Pictorial representation: Figure 1: The dihybrid cross between $RrTT \times rrTt$

Fig. 1: The dihybrid cross between $RrTT \times rrTt$

Answer 8

Expert Solution & Answer

Explanation of Solution

In a dihybrid cross, the dominant trait needs at least one form of the allele for its expression and recessive trait needs both alleles for its expression. The phenotypic ratio of dihybrid cross is $9: 3: 3: 1$ .

The cross between parental traits did not produce any offspring with both recessive traits (rrtt) and thus the possibility of an offspring having both recessive traits when a plant with $RrTT$ is crossed with a plant with $rrTt$ is zero.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Conclusion

From the punnett square it is clear that the chances of getting an offspring having both recessive trait is none when the parents of $RrTT$ and $rrTt$ genotypes are crossed.

Answer 12

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