a.
Define the normal body temperature, and explain in briefly.
a.
Explanation of Solution
Discussion:
The value of normal temperature of a human body can varies from
The normal temperature of human body also changes due the muscle metabolism while doing daily exercises.
The normal temperature of a human body can varies from
b.
State the temperature range that referred as fever and explain in briefly..
b.
Explanation of Solution
The normal temperature of a human body can varies from
Using the knowledge of the temperature ranges of human body it easy to identify the illness and health condition and also it is easy to provide proper medication for the affected person.
c.
State the normal surface temperature of a human body and explain briefly.
c.
Explanation of Solution
The normal surface temperature (skin temperature ) of a human body is exists between
Generally, in humans pregnant ladies have the high surface temperature due increased blood pressure. Children’s skin temperature is a bit higher than the adults.
d.
State the comfortable room temperature, and explain significance in terms of human thermal comfort. Explain the role of humidity.
d.
Explanation of Solution
According to the standards of the WHO (worlds health organization) the normal comfortable room temperature is
Generally for healthy adults comfortable room temperature is
The water vapor percentage in the air is known as humidity or humidity factor. It is the environmental factor that affects the human thermal comfort
For example, the comfortable room temperature for human body is 40 to 50% of relative humidity and
Humidity increases the body temperature because of overheat, and increases the moisture in the air. Humidity might cause for the dangerous health issues.
If a person doing some exercise, that person can feel more comfortable in a room that has lower than
e.
Investigate the value of operating temperature range of the freezer in a household temperature.
e.
Explanation of Solution
The household refrigerator temperature is about or below the
The frozen food is that which requires keep storing in cool place under frozen temperatures from its prepared time to eaten.
Thus, the temperature of the freezer of a household refrigerator is
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Chapter 11 Solutions
EP WEBASSIGN FOR MOAVENI'S ENGINEERING
- A steel rod 100 ft long holds a 200 lb weight as shown. If the diameter of the circular rod is ¼ inch, find the maximum normal stress in the road, taking into account the weight of the rod itself. Use: density of steel = ϒ = 490 lb/ft3 .arrow_forwardضهقعفكضكشتبتلتيزذظظؤوروىووؤءظكصحبت٢٨٩٤٨٤ع٣خ٩@@@#&#)@)arrow_forwardضهقعفكضكشتبتلتيزذظظؤوروىووؤءظكصحبت٢٨٩٤٨٤ع٣خ٩@@@#&#)@)arrow_forward
- A square flexible foundation of width B applies a uniform pressure go to the underlying ground. (a) Determine the vertical stress increase at a depth of 0.5B below the center using Aσ beneath the corner of a uniform rectangular load given by Aσ Variation of Influence Value I m n 0.5 0.6 0.8 1.0 0.2 0.4 0.2 0.01790 0.03280 0.03866 0.04348 0.05042 0.05471 0.4 0.03280 0.06024 0.07111 0.08009 0.09314 0.10129 0.5 0.03866 0.07111 0.08403 0.09473 0.11035 0.12018 0.6 0.04348 0.08009 0.09473 0.10688 0.12474 0.13605 0.8 0.05042 0.09314 0.11035 0.12474 0.14607 0.15978 1.0 0.05471 0.10129 0.12018 0.13605 0.15978 0.17522 (Enter your answer to three significant figures.) Ασ/90 = Activity Frame (b) Determine the vertical stress increase at a depth of 0.5B below the center using the 2 : 1 method equation below. 90 x B x L Aσ = (B+ z) (L+ z) (Enter your answer to three significant figures.) Δσ/90 = (c) Determine the vertical stress increase at a depth of 0.5B below the center using stress isobars in…arrow_forwardNeed help!!!arrow_forward2 A flexible circular area is subjected to a uniformly distributed load of 450 kN/m² (the figure below). The diameter of the load area is 2 m. Estimate the average stress increase (Aσay) below the center of the loaded area between depths of 3 m and 6 m. H₂ 1.0 H₂ B 0.8 CHI HD DV 0.6 C 1.0 1.5 0.4 0.2 6.0 8.0. 10.0 2.0 2.5 3.0 4.0 5.0 H₁ (Enter your answer to two significant figures.) Δσαν τ kN/m² 6arrow_forward
- Refer to the figure below. Using the procedure outlined in your textbook, determine the average stress increase in the clay layer below the center of the foundation due to the net foundation load of 45 tons. Use the equations: Aσ = and qo x B x L (B+ z)(L+ z) Aσ av (H2/H₁) Δσι +44 + Δσο net load 6 4:5 ft 10 ft 5ft x 5ft Sand Sand y=100 lb/ft³ Ysat 122 lb/ft³:" Ysat 120 lb/ft³: 0.7 C=0.25 Groundwater table C=0.06 Preconsolidation pressure = 2000 lb/ft² (Enter your answer to three significant figures.) Ασαν = lb/ft²arrow_forwardRefer to the figure below, which shows a flexible rectangular area. Given: B₁ = 4 ft, B₂ = 6 ft, L₁ = 8 ft, and L2 = 10 ft. If the area is subjected to a uniform load of 4100 lb/ft², determine the stress increase at a depth of 10 ft located immediately below point O. Use the table below. T B(1) 3 B(2) 2 L(1) * 4 L2) Table 1 Variation of Influence Value I n m 0.8 0.9 1.0 1.2 1.4 0.1 0.02576 0.02698 0.02794 0.02926 0.03007 0.2 0.05042 0.05283 0.05471 0.05733 0.05894 0.3 0.07308 0.07661 0.07938 0.08323 0.08561 0.4 0.09314 0.09770 0.10129 0.10631 0.10941 0.5 0.11035 0.11584 0.12018 0.12626 0.13003 0.6 0.12474 0.13105 0.13605 0.14309 0.14749 0.7 0.13653 0.14356 0.14914 0.15703 0.16199 0.8 0.14607 0.15371 0.15978 0.16843 0.17389 0.9 0.15371 0.16185 0.16835 0.1766 0.18357 1.0 0.15978 0.16835 0.17522 0.18508 0.19139 1.1 0.16843 0.17766 0.18508 0.19584 0.20278 (Enter your answer to three significant figures.) Aσ = lb/ft²arrow_forwardPoint loads of magnitude 100, 200, and 380 kN act at B, C, and D, respectively (in the figure below). Determine the increase in vertical stress at a depth of 6 m below point A. Use Boussinesq's equation. B 6 m A 6 m с 3 m D (Enter your answer to three significant figures.) Δαχτ kN/m²arrow_forward
- Two line loads q₁ = 30 kN/m and 92 = 44 kN/m of infinite lengths are acting on top of an elastic medium, as shown in the figure below. Find the vertical stress increase at A. 92 91 6 m 3 m 3 m Δσ A (Enter your answer to three significant figures.) Vertical stress increase at A = kN/m²arrow_forwardA flexible circular area is subjected to a uniformly distributed load of 144 kN/m² (see the figure below). The diameter of the load area is 2 m. Estimate the average stress increase (Aσay) below the center of the loaded area between depths of 3 m and 6 m. Use the equations: 1 Ασ = go 1 [1 + (2) ² ³/2 and Aσ av (H2/H1) Δσι + 41ση + Ασο 6 9 B/2 krark do Δε Aσ (Enter your answer to three significant figures.) Ασαν = kN/m²arrow_forwardIn construction what is the difference in general requirements specific project requirements?arrow_forward
- Engineering Fundamentals: An Introduction to Engi...Civil EngineeringISBN:9781305084766Author:Saeed MoaveniPublisher:Cengage Learning