Study Guide with Lab Manual for Jeffus' Welding: Principles and Applications, 8th
8th Edition
ISBN: 9781305494701
Author: Larry Jeffus
Publisher: Cengage Learning
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Chapter 11, Problem 18R
What are the advantages of using
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An AISI 1018 steel ball with 1.100-in diameter is used as a roller between a flat plate
made from 2024 T3 aluminum and a flat table surface made from ASTM No. 30 gray
cast iron. Determine the maximum amount of weight that can be stacked on the
aluminum plate without exceeding a maximum shear stress of 19.00 kpsi in any of the
three pieces. Assume the figure given below, which is based on a typical Poisson's
ratio of 0.3, is applicable to estimate the depth at which the maximum shear stress
occurs for these materials.
1.0
0.8
Ratio of stress to Pmax
0.4
90
0.6
στ
Tmax
0.2
0.5a
a
1.5a
2a
2.5a
За
Distance from contact surface
The maximum amount of weight that can be stacked on the aluminum plate is
lbf.
A carbon steel ball with 27.00-mm diameter is pressed together with an aluminum ball
with a 36.00-mm diameter by a force of 11.00 N. Determine the maximum shear
stress and the depth at which it will occur for the aluminum ball. Assume the figure
given below, which is based on a typical Poisson's ratio of 0.3, is applicable to estimate
the depth at which the maximum shear stress occurs for these materials.
1.0
0.8
Ratio of stress to Pma
9 0.6
στ
24
0.4
Tmax
0.2
0
0.5a
a
1.5a
Z
2a
2.5a
За
Distance from contact surface
The maximum shear stress is determined to be
MPa.
The depth in the aluminum ball at which the maximum shear stress will occur is
determined to be [
mm.
Chapter 11 Solutions
Study Guide with Lab Manual for Jeffus' Welding: Principles and Applications, 8th
Ch. 11 - What items make up a basic semiautomatic welding...Ch. 11 - What must be done to the shielding gas cylinder...Ch. 11 - Why is the shielding gas valve "cracked" before...Ch. 11 - What causes the electrode to bird-nest?Ch. 11 - Why must all fittings and connections be tight?Ch. 11 - What parts should be activated by depressing the...Ch. 11 - What benefit does a welding wire's cast provide?Ch. 11 - What are the advantages of using a feed roller...Ch. 11 - Why should the feed roller drag prevent the spool...Ch. 11 - Why must you always wind the wire tightly into a...
Ch. 11 - How is the amperage adjusted on a GMA welder?Ch. 11 - What effect on the welding current does increasing...Ch. 11 - Using Table 11-1, determine the amperage if 400...Ch. 11 - What happens to the weld as the electrode...Ch. 11 - What is the effect on the weld of changing the...Ch. 11 - What are the advantages of adding oxygen or CO2 to...Ch. 11 - What reactive gases are used with argon for GMA...Ch. 11 - What are the advantages of using CO2 for making...Ch. 11 - What is mill scale?Ch. 11 - What type of porosity is most often caused by mill...Ch. 11 - What should the welder watch if the view of the...Ch. 11 - When making a vertical weld and it appears that...Ch. 11 - What are the advantages of making vertical down...Ch. 11 - How can small weld beads be maintained during...Ch. 11 - How can spatter be controlled on the nozzle when...
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- Show all work pleasearrow_forwardDraw top, side, front view With pen(cil) and paper Multi view drawing and handwriting all of itarrow_forwardA wheel of diameter 150.0 mm and width 37.00 mm carrying a load 2.200 kN rolls on a flat rail. Take the wheel material as steel and the rail material as cast iron. Assume the figure given, which is based on a Poisson's ratio of 0.3, is applicable to estimate the depth at which the maximum shear stress occurs for these materials. At this critical depth, calculate the Hertzian stresses σr, σy, σz, and Tmax for the wheel. 1.0 0.8 0, т Ratio of stress to Pmax 0.4 0.6 90 69 0.2 0.5b b 1.5b Tmax 2b Distance from contact surface The Hertizian stresses are as follows: 02 = or = -23.8 psi for the wheel =| necessary.) σy for the wheel =| MPa σz for the wheel = MPa V4 for the wheel = | MPa 2.5b ཡི 3b MPa (Include a minus sign ifarrow_forward
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