Explanation Given: 10.0 g Kr 10.0 g Xe 10.0 g He STP stands for standard temperature and pressure where volume is 22.4 L mole −1 , standard temperature is 0 ° or 273 K and standard pressure is 1 atm. The volume occupies by 1 mole of any gas at STP is called the molar volume. Avogadro’s law : Equal volumes of gases under the same condition of temperature and pressure have same number of particles in other words one mole of any gas at the same temperature and same pressure condition have the same volume. According to Avogadro’s hypothesis at STP, 1 mol of any gas which contains 6.02 × 10 23 particles, occupies 22.4 L volume. Formula used: Nuber of moles = amount in g molar mass Calculation: a. 10.0 g Kr First calculate the number of moles of Kr gas in 10.0 g as follows: The molar mass of Kr = 83.798 gl mol Number of moles = amount in g molar mass Number of moles = 10 . 0 g 83 . 798 g / m o l To calculate the volume in liters occupied by 0.119 mole of Kr gas at STP uses the following expression:

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Chapter 11, Problem 146E

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To determine:

In the given gases, which gas has the greatest volume at STP

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Chapter 11, Problem 145E

Chapter 11, Problem 147E

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In the given gases, which gas has the greatest volume at STP

Solution Summary: The author calculates the molar volume of any gas at STP, based on Avogadro's law.

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To determine: In the given gases, which gas has the greatest volume at STP

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Chapter 11 Solutions

To determine:

In the given gases, which gas has the greatest volume at STP