Explanation Given: The decomposition equations are: 2NH 3 (g)→N 2 (g)+3H 2 (g) N 2 H 4 (g)→N 2 (g)+2H 2 (g) Initial temperature =300K Initial pressure =0.5 atm Temperature during heating =1200 K Pressure after heating =4.5 atm Formula used: PV=nRT where P=pressure V=Volume T=temperature n=moles R=gas constant=0.0821 L atm/mol K Calculation: Let the initial mole of two gases is one. Let moles of N 2 H 4 =x So, moles of NH 3 =1×x As per balanced equation, 2NH 3 (g)→N 2 (g)+3H 2 (g) On complete decomposition two moles of ammonia will give one mole of nitrogen and three moles of hydrogen. So, with decomposition of each mole of ammonia gas we will get total two moles of product gases. Therefore 1×x moles of ammonia gas will give 2(1-x) moles of product gases Similarly, according to equation, N 2 H 4 (g)→N 2 (g)+2H 2 (g) One mole of hydrazine will give three moles of product gases Therefore x mole of it will give 3x moles of product gases The volume of container before and after heating is same, say “V” According to ideal gas equation PV=nRT where p =total pressure of gas V =Volume of gas/ container=V R =Gas constant=0...

Chemistry: Structure and Properties Plus MasteringChemistry with eText -- Access Card Package

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ISBN: 9780321729736

Author: Nivaldo J. Tro

Publisher: PEARSON

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Chapter 11, Problem 131E

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To determine:

The percent of N₂H₄(g) in the original mixture of N₂H₄(g)and NH₃(g).

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Chapter 11, Problem 130E

Chapter 11, Problem 132E

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The percent of N 2 H 4 (g) in the original mixture of N 2 H 4 (g)and NH 3 (g).

Solution Summary: The author explains how to determine the percent of N 2 H 4 (g) in the mixture.

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To determine:

The percent of N₂H₄(g) in the original mixture of N₂H₄(g)and NH₃(g).

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Chapter 11 Solutions

The percent of N 2 H 4 (g) in the original mixture of N 2 H 4 (g)and NH 3 (g).

Solution Summary: The author explains how to determine the percent of N 2 H 4 (g) in the mixture.

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To determine: The percent of N2H4(g) in the original mixture of N2H4(g)and NH3(g).

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Chapter 11 Solutions

To determine:

The percent of N₂H₄(g) in the original mixture of N₂H₄(g)and NH₃(g).