Chapter 11, Problem 11.73QP

Interpretation Introduction

Interpretation: The melting point of an aqueous solution made by adding $1\text{86}\text{mg}$ of saccharin $\left({\text{C}}_{\text{7}}{\text{H}}_{\text{5}}{\text{O}}_{\text{3}}\text{NS}\right)$ to $1.00\text{mL}$ of water is to be stated.

Concept introduction: The addition of substance (solute) in a solvent is known as dissolution. After the process of dissolution the boiling point of solvent increases and the freezing point decreases. The freezing point of the solvent is reverse of the melting point. The melting point of the given solution is calculated by the lowering of freezing point for the given amount of solvent.

To determine: The melting point of an aqueous solution made by adding $1\text{86}\text{mg}$ of saccharin $\left({\text{C}}_{\text{7}}{\text{H}}_{\text{5}}{\text{O}}_{\text{3}}\text{NS}\right)$ to $1.00\text{mL}$ of water.