CHEMISTRY:SCI.IN CONTEXT (CL)-PACKAGE
CHEMISTRY:SCI.IN CONTEXT (CL)-PACKAGE
5th Edition
ISBN: 9780393628173
Author: Gilbert
Publisher: NORTON
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Chapter 11, Problem 11.67QP
Interpretation Introduction

Interpretation: The concentration of six important elements that are present in river water is given. The molality of these six different elements is to be calculated.

Concept introduction: Molality is defined as the number of moles of solute that is present in 1kg of solvent.

To determine: The molality of given six different elements that are present in the river water.

Expert Solution & Answer
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Answer to Problem 11.67QP

Solution

The molality of Ammonia is 0.07×10-3mol/kg_ .

The molality of NO2 is 0.009×10-3mol/kg_ .

The molality of NO3 is 21.98×10-3mol/kg_ .

Explanation of Solution

Explanation

Given

The lethal concentration of Ammonia is 1.1mg/L .

The lethal concentration of Nitrite ion is 0.40mg/L .

The lethal concentration of Nitrate ion is 1361mg/L .

Density of solution is 1g/mL .

The conversion of mg into kg is done as,

1mg=0.000001g

Hence, the conversion of 1.1mg into kg is done as,

1.1mg=1.1×0.000001kg=1.1×106kg

Similarly, the conversion of 0.40mg into kg is done as,

0.40mg=0.40×0.000001kg=0.4×106kg

Similarly, the conversion of 1361mg into kg is done as,

1361mg=1361×0.000001kg=1361×106kg

The mass of NH3 in 1L of solution is 1.1×106kg .

The mass of Nitrite ion in 1L of solution is 0.4×106kg .

The mass of Nitrate ion in 1L of solution is 1361×106kg .

Total mass of solute =Mass of Ammonia+Mass of Nitrite ion+Mass of Nitrate ion=1.1×106kg+0.4×106kg+1361×106kg=1362.5×106kg=1.363×103kg

The conversion of g into kg is done as,

1g=0.001kg

The conversion of mL into L is done as,

1mL=0.001L

The mass of solution is for 0.001L of the solution =103kg .

The mass of solution is for 1L of the solution =1030.001kg=1kg

The total mass of solution is given as,

Total mass of solution=Mass of solvent+Mass of solute

Substitute the mass of solution and solvent in the above equation,

Total mass of solution=Mass of solvent+Mass of solute1kg=Mass of solvent+1.363×103kgMass of solvent=0.999kg

The molar mss of NH3 is calculated as,

Molar mass of NH3=(1×Molar mass of N+3×Molar mass of H)=(1×14.0g/mol+3×1.008g/mol)=17.024g/mol

The molar mss of NO2 is calculated as,

Molar mass of NO2=(1×Molar mass of N+2×Molar mass of O)=(1×14.0g/mol+2×15.99g/mol)=45.98g/mol

The molar mss of NO3 is calculated as,

Molar mass of NO3=(1×Molar mass of N+3×Molar mass of O)=(1×14.0g/mol+3×15.99g/mol)=61.97g/mol

The number of moles of a substance is calculated as,

Number of moles=Given massMolar mass (1)

Substitute the value of given mass and molar mass of Ammonia in the above equation as,

Number of moles=Given massMolar mass=1.1×106kg17.024×103kgmol=0.065×103mol

Similarly, substitute the value of given mass and molar mass of NO2 in the equation (1),

Number of moles=Given massMolar mass=0.4×106kg45.98×103kgmol=0.0087×103mol

Similarly, substitute the value of given mass and molar mass of NO3 in the equation (1),

Number of moles=Given massMolar mass=1361×106kg61.97×103kgmol=21.96×103mol

The molality of the solution is calculated as,

Molality=Number of moles of soluteMass of solvent in kg (2)

Substitute the number of moles of Ammonia and mass of solvent in the above equation,

Molality=0.065×103mol0.999kg=0.07×10-3mol/kg_

The molality of Ammonia is 0.07×10-3mol/kg_ .

Similarly, substitute the number of moles of NO2 and mass of solvent in the equation (2),

Molality=0.0087×103mol0.999kg=0.009×10-3mol/kg_

The molality of NO2 is 0.009×10-3mol/kg_ .

Similarly, substitute the number of moles of NO3 and mass of solvent in the equation (2),

Molality=21.96×103mol0.999kg=21.98×10-3mol/kg_

The molality of NO3 is 21.98×10-3mol/kg_ .

Conclusion

The molality of Ammonia is 0.07×10-3mol/kg_ .

The molality of NO2 is 0.009×10-3mol/kg_ .

The molality of NO3 is 21.98×10-3mol/kg_ .

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Chapter 11 Solutions

CHEMISTRY:SCI.IN CONTEXT (CL)-PACKAGE

Ch. 11.5 - Prob. 11PECh. 11.5 - Prob. 12PECh. 11.5 - Prob. 13PECh. 11.5 - Prob. 14PECh. 11.5 - Prob. 15PECh. 11.6 - Prob. 16PECh. 11.6 - Prob. 17PECh. 11 - Prob. 11.1VPCh. 11 - Prob. 11.2VPCh. 11 - Prob. 11.3VPCh. 11 - Prob. 11.4VPCh. 11 - Prob. 11.5VPCh. 11 - Prob. 11.6VPCh. 11 - Prob. 11.7VPCh. 11 - Prob. 11.8QPCh. 11 - Prob. 11.9QPCh. 11 - Prob. 11.10QPCh. 11 - Prob. 11.11QPCh. 11 - Prob. 11.12QPCh. 11 - Prob. 11.13QPCh. 11 - Prob. 11.14QPCh. 11 - Prob. 11.15QPCh. 11 - Prob. 11.16QPCh. 11 - Prob. 11.17QPCh. 11 - Prob. 11.18QPCh. 11 - Prob. 11.19QPCh. 11 - Prob. 11.20QPCh. 11 - Prob. 11.21QPCh. 11 - Prob. 11.22QPCh. 11 - Prob. 11.23QPCh. 11 - Prob. 11.24QPCh. 11 - Prob. 11.25QPCh. 11 - Prob. 11.26QPCh. 11 - Prob. 11.27QPCh. 11 - Prob. 11.28QPCh. 11 - Prob. 11.29QPCh. 11 - Prob. 11.30QPCh. 11 - Prob. 11.31QPCh. 11 - Prob. 11.32QPCh. 11 - Prob. 11.33QPCh. 11 - Prob. 11.34QPCh. 11 - Prob. 11.35QPCh. 11 - Prob. 11.36QPCh. 11 - Prob. 11.37QPCh. 11 - Prob. 11.38QPCh. 11 - Prob. 11.39QPCh. 11 - Prob. 11.40QPCh. 11 - Prob. 11.41QPCh. 11 - Prob. 11.42QPCh. 11 - Prob. 11.43QPCh. 11 - Prob. 11.44QPCh. 11 - Prob. 11.45QPCh. 11 - Prob. 11.46QPCh. 11 - Prob. 11.47QPCh. 11 - Prob. 11.48QPCh. 11 - Prob. 11.49QPCh. 11 - Prob. 11.50QPCh. 11 - Prob. 11.51QPCh. 11 - Prob. 11.52QPCh. 11 - Prob. 11.53QPCh. 11 - Prob. 11.54QPCh. 11 - Prob. 11.55QPCh. 11 - Prob. 11.56QPCh. 11 - Prob. 11.57QPCh. 11 - Prob. 11.58QPCh. 11 - Prob. 11.59QPCh. 11 - Prob. 11.60QPCh. 11 - Prob. 11.61QPCh. 11 - Prob. 11.62QPCh. 11 - Prob. 11.63QPCh. 11 - Prob. 11.64QPCh. 11 - Prob. 11.65QPCh. 11 - Prob. 11.66QPCh. 11 - Prob. 11.67QPCh. 11 - Prob. 11.68QPCh. 11 - Prob. 11.69QPCh. 11 - Prob. 11.70QPCh. 11 - Prob. 11.71QPCh. 11 - Prob. 11.72QPCh. 11 - Prob. 11.73QPCh. 11 - Prob. 11.74QPCh. 11 - Prob. 11.75QPCh. 11 - Prob. 11.76QPCh. 11 - Prob. 11.77QPCh. 11 - Prob. 11.78QPCh. 11 - Prob. 11.79QPCh. 11 - Prob. 11.80QPCh. 11 - Prob. 11.81QPCh. 11 - Prob. 11.82QPCh. 11 - Prob. 11.83QPCh. 11 - Prob. 11.84QPCh. 11 - Prob. 11.85QPCh. 11 - Prob. 11.86QPCh. 11 - Prob. 11.87QPCh. 11 - Prob. 11.88QPCh. 11 - Prob. 11.89QPCh. 11 - Prob. 11.90QPCh. 11 - Prob. 11.91QPCh. 11 - Prob. 11.92QPCh. 11 - Prob. 11.93QPCh. 11 - Prob. 11.94QPCh. 11 - Prob. 11.95APCh. 11 - Prob. 11.96APCh. 11 - Prob. 11.97APCh. 11 - Prob. 11.98APCh. 11 - Prob. 11.99APCh. 11 - Prob. 11.100APCh. 11 - Prob. 11.101APCh. 11 - Prob. 11.102APCh. 11 - Prob. 11.103APCh. 11 - Prob. 11.104APCh. 11 - Prob. 11.105APCh. 11 - Prob. 11.106AP
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Solutions: Crash Course Chemistry #27; Author: Crash Course;https://www.youtube.com/watch?v=9h2f1Bjr0p4;License: Standard YouTube License, CC-BY