The formation of given compound from 3-methyl-1-butyne has to be shown. Concept introduction: Addition reaction: Alkene reacts with polar reagent (HBr, HCl) across the double bond, leads to the product of alkyl halide . Markovnikov’s rule: In the overall addition reaction, the hydrogen atom (electrophile) is bonded to least substituted carbon and nucleophile is bonded to the most substituted carbon. This is known as Markovnikov’s rule.

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Answer 1

Question

Chapter 11, Problem 11.59QP

a)

Interpretation Introduction

Interpretation:

The formation of given compound from 3-methyl-1-butyne has to be shown.

Concept introduction:

Addition reaction: Alkene reacts with polar reagent (HBr, HCl) across the double bond, leads to the product of alkyl halide.

Markovnikov’s rule:

In the overall addition reaction, the hydrogen atom (electrophile) is bonded to least substituted carbon and nucleophile is bonded to the most substituted carbon. This is known as Markovnikov’s rule.

b)

Interpretation Introduction

Interpretation:

The formation of given compound from 3-methyl-1-butyne has to be shown.

Concept introduction:

Addition reaction: Alkene reacts with polar reagent (HBr, HCl) across the double bond, leads to the product of alkyl halide.

Addition of bromine across the double bond in the presence of Lewis catalyst undergoes addition reaction leads to formation of products.

Markovnikov’s rule:

In the overall reaction, the hydrogen atom (electrophile) is bonded to least substituted carbon and nucleophile is bonded to the most substituted carbon. This is known as Markovnikov’s rule.

c)

Interpretation Introduction

Interpretation:

The formation of given compound from 3-methyl-1-butyne has to be shown.

Concept introduction:

Addition reaction: Alkene reacts with polar reagent (HBr, HCl) across the double bond, leads to the product of alkyl halide (Or)

Hydrogenation of alkene: Addition of hydrogen molecule across the double bond in presence of catalyst undergoes hydrogenation of alkene.

Markovnikov’s rule:

In the overall reaction, the hydrogen atom (electrophile) is bonded to least substituted carbon and nucleophile is bonded to the most substituted carbon. This is known as Markovnikov’s rule.

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Students have asked these similar questions

1. Which one(s) of these can be oxidized with CrO3 ? (could be more than one) a) triphenylmethanol b) 2-pentanol c) Ethyl alcohol d) CH3 2. Write in all the product(s) of this reaction. Label them as "major" or "minor". 2-methyl-2-hexanol H2SO4, heat

3) Determine if the pairs are constitutional isomers, enantiomers, diastereomers, or mesocompounds. (4 points)

In the decomposition reaction in solution B → C, only species C absorbs UV radiation, but neither B nor the solvent absorbs. If we call At the absorbance measured at any time, A0 the absorbance at the beginning of the reaction, and A∞ the absorbance at the end of the reaction, which of the expressions is valid? We assume that Beer's law is fulfilled.

Answer 2

Question

Chapter 11, Problem 11.59QP

a)

Interpretation Introduction

Interpretation:

The formation of given compound from 3-methyl-1-butyne has to be shown.

Concept introduction:

Addition reaction: Alkene reacts with polar reagent (HBr, HCl) across the double bond, leads to the product of alkyl halide.

Markovnikov’s rule:

In the overall addition reaction, the hydrogen atom (electrophile) is bonded to least substituted carbon and nucleophile is bonded to the most substituted carbon. This is known as Markovnikov’s rule.

b)

Interpretation Introduction

Interpretation:

The formation of given compound from 3-methyl-1-butyne has to be shown.

Concept introduction:

Addition reaction: Alkene reacts with polar reagent (HBr, HCl) across the double bond, leads to the product of alkyl halide.

Addition of bromine across the double bond in the presence of Lewis catalyst undergoes addition reaction leads to formation of products.

Markovnikov’s rule:

In the overall reaction, the hydrogen atom (electrophile) is bonded to least substituted carbon and nucleophile is bonded to the most substituted carbon. This is known as Markovnikov’s rule.

c)

Interpretation Introduction

Interpretation:

The formation of given compound from 3-methyl-1-butyne has to be shown.

Concept introduction:

Addition reaction: Alkene reacts with polar reagent (HBr, HCl) across the double bond, leads to the product of alkyl halide (Or)

Hydrogenation of alkene: Addition of hydrogen molecule across the double bond in presence of catalyst undergoes hydrogenation of alkene.

Markovnikov’s rule:

In the overall reaction, the hydrogen atom (electrophile) is bonded to least substituted carbon and nucleophile is bonded to the most substituted carbon. This is known as Markovnikov’s rule.

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Answer 3

Question

Chapter 11, Problem 11.59QP

a)

Interpretation Introduction

Interpretation:

The formation of given compound from 3-methyl-1-butyne has to be shown.

Concept introduction:

Addition reaction: Alkene reacts with polar reagent (HBr, HCl) across the double bond, leads to the product of alkyl halide.

Markovnikov’s rule:

In the overall addition reaction, the hydrogen atom (electrophile) is bonded to least substituted carbon and nucleophile is bonded to the most substituted carbon. This is known as Markovnikov’s rule.

b)

Interpretation Introduction

Interpretation:

The formation of given compound from 3-methyl-1-butyne has to be shown.

Concept introduction:

Addition reaction: Alkene reacts with polar reagent (HBr, HCl) across the double bond, leads to the product of alkyl halide.

Addition of bromine across the double bond in the presence of Lewis catalyst undergoes addition reaction leads to formation of products.

Markovnikov’s rule:

In the overall reaction, the hydrogen atom (electrophile) is bonded to least substituted carbon and nucleophile is bonded to the most substituted carbon. This is known as Markovnikov’s rule.

c)

Interpretation Introduction

Interpretation:

The formation of given compound from 3-methyl-1-butyne has to be shown.

Concept introduction:

Addition reaction: Alkene reacts with polar reagent (HBr, HCl) across the double bond, leads to the product of alkyl halide (Or)

Hydrogenation of alkene: Addition of hydrogen molecule across the double bond in presence of catalyst undergoes hydrogenation of alkene.

Markovnikov’s rule:

In the overall reaction, the hydrogen atom (electrophile) is bonded to least substituted carbon and nucleophile is bonded to the most substituted carbon. This is known as Markovnikov’s rule.

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Answer 4

Question

Chapter 11, Problem 11.59QP

a)

Interpretation Introduction

Interpretation:

The formation of given compound from 3-methyl-1-butyne has to be shown.

Concept introduction:

Addition reaction: Alkene reacts with polar reagent (HBr, HCl) across the double bond, leads to the product of alkyl halide.

Markovnikov’s rule:

In the overall addition reaction, the hydrogen atom (electrophile) is bonded to least substituted carbon and nucleophile is bonded to the most substituted carbon. This is known as Markovnikov’s rule.

b)

Interpretation Introduction

Interpretation:

The formation of given compound from 3-methyl-1-butyne has to be shown.

Concept introduction:

Addition reaction: Alkene reacts with polar reagent (HBr, HCl) across the double bond, leads to the product of alkyl halide.

Addition of bromine across the double bond in the presence of Lewis catalyst undergoes addition reaction leads to formation of products.

Markovnikov’s rule:

In the overall reaction, the hydrogen atom (electrophile) is bonded to least substituted carbon and nucleophile is bonded to the most substituted carbon. This is known as Markovnikov’s rule.

c)

Interpretation Introduction

Interpretation:

The formation of given compound from 3-methyl-1-butyne has to be shown.

Concept introduction:

Addition reaction: Alkene reacts with polar reagent (HBr, HCl) across the double bond, leads to the product of alkyl halide (Or)

Hydrogenation of alkene: Addition of hydrogen molecule across the double bond in presence of catalyst undergoes hydrogenation of alkene.

Markovnikov’s rule:

In the overall reaction, the hydrogen atom (electrophile) is bonded to least substituted carbon and nucleophile is bonded to the most substituted carbon. This is known as Markovnikov’s rule.

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Answer 5

Chapter 11, Problem 11.59QP

a)

Interpretation Introduction

Interpretation:

The formation of given compound from 3-methyl-1-butyne has to be shown.

Concept introduction:

Addition reaction: Alkene reacts with polar reagent (HBr, HCl) across the double bond, leads to the product of alkyl halide.

Markovnikov’s rule:

In the overall addition reaction, the hydrogen atom (electrophile) is bonded to least substituted carbon and nucleophile is bonded to the most substituted carbon. This is known as Markovnikov’s rule.

b)

Interpretation Introduction

Interpretation:

The formation of given compound from 3-methyl-1-butyne has to be shown.

Concept introduction:

Addition reaction: Alkene reacts with polar reagent (HBr, HCl) across the double bond, leads to the product of alkyl halide.

Addition of bromine across the double bond in the presence of Lewis catalyst undergoes addition reaction leads to formation of products.

Markovnikov’s rule:

In the overall reaction, the hydrogen atom (electrophile) is bonded to least substituted carbon and nucleophile is bonded to the most substituted carbon. This is known as Markovnikov’s rule.

c)

Interpretation Introduction

Interpretation:

The formation of given compound from 3-methyl-1-butyne has to be shown.

Concept introduction:

Addition reaction: Alkene reacts with polar reagent (HBr, HCl) across the double bond, leads to the product of alkyl halide (Or)

Hydrogenation of alkene: Addition of hydrogen molecule across the double bond in presence of catalyst undergoes hydrogenation of alkene.

Markovnikov’s rule:

In the overall reaction, the hydrogen atom (electrophile) is bonded to least substituted carbon and nucleophile is bonded to the most substituted carbon. This is known as Markovnikov’s rule.

Answer 6

Chapter 11, Problem 11.59QP

a)

Interpretation Introduction

Interpretation:

The formation of given compound from 3-methyl-1-butyne has to be shown.

Concept introduction:

Addition reaction: Alkene reacts with polar reagent (HBr, HCl) across the double bond, leads to the product of alkyl halide.

Markovnikov’s rule:

In the overall addition reaction, the hydrogen atom (electrophile) is bonded to least substituted carbon and nucleophile is bonded to the most substituted carbon. This is known as Markovnikov’s rule.

Answer 7

Chapter 11, Problem 11.59QP

a)

Interpretation Introduction

Interpretation:

The formation of given compound from 3-methyl-1-butyne has to be shown.

Concept introduction:

Addition reaction: Alkene reacts with polar reagent (HBr, HCl) across the double bond, leads to the product of alkyl halide.

Markovnikov’s rule:

In the overall addition reaction, the hydrogen atom (electrophile) is bonded to least substituted carbon and nucleophile is bonded to the most substituted carbon. This is known as Markovnikov’s rule.

Answer 8

b)

Interpretation Introduction

Interpretation:

The formation of given compound from 3-methyl-1-butyne has to be shown.

Concept introduction:

Addition reaction: Alkene reacts with polar reagent (HBr, HCl) across the double bond, leads to the product of alkyl halide.

Addition of bromine across the double bond in the presence of Lewis catalyst undergoes addition reaction leads to formation of products.

Markovnikov’s rule:

In the overall reaction, the hydrogen atom (electrophile) is bonded to least substituted carbon and nucleophile is bonded to the most substituted carbon. This is known as Markovnikov’s rule.

Answer 9

b)

Interpretation Introduction

Interpretation:

The formation of given compound from 3-methyl-1-butyne has to be shown.

Concept introduction:

Addition reaction: Alkene reacts with polar reagent (HBr, HCl) across the double bond, leads to the product of alkyl halide.

Addition of bromine across the double bond in the presence of Lewis catalyst undergoes addition reaction leads to formation of products.

Markovnikov’s rule:

In the overall reaction, the hydrogen atom (electrophile) is bonded to least substituted carbon and nucleophile is bonded to the most substituted carbon. This is known as Markovnikov’s rule.

Answer 10

c)

Interpretation Introduction

Interpretation:

The formation of given compound from 3-methyl-1-butyne has to be shown.

Concept introduction:

Addition reaction: Alkene reacts with polar reagent (HBr, HCl) across the double bond, leads to the product of alkyl halide (Or)

Hydrogenation of alkene: Addition of hydrogen molecule across the double bond in presence of catalyst undergoes hydrogenation of alkene.

Markovnikov’s rule:

In the overall reaction, the hydrogen atom (electrophile) is bonded to least substituted carbon and nucleophile is bonded to the most substituted carbon. This is known as Markovnikov’s rule.

Answer 11

c)

Interpretation Introduction

Interpretation:

The formation of given compound from 3-methyl-1-butyne has to be shown.

Concept introduction:

Addition reaction: Alkene reacts with polar reagent (HBr, HCl) across the double bond, leads to the product of alkyl halide (Or)

Hydrogenation of alkene: Addition of hydrogen molecule across the double bond in presence of catalyst undergoes hydrogenation of alkene.

Markovnikov’s rule:

In the overall reaction, the hydrogen atom (electrophile) is bonded to least substituted carbon and nucleophile is bonded to the most substituted carbon. This is known as Markovnikov’s rule.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 11.2 - Prob. 1PE Ch. 11.2 - Prob. 2PE Ch. 11.2 - Prob. 3PE Ch. 11.2 - Prob. 1RC Ch. 11.3 - Prob. 1RC Ch. 11.4 - Prob. 1PE Ch. 11.4 - Prob. 1RC Ch. 11.5 - Prob. 1PE Ch. 11.5 - Prob. 1RC Ch. 11 - Prob. 11.1QP

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