(a)
Interpretation:
The atomic orbitals that mix to form the hybrid orbitals of nitrogen atom in
Concept introduction:
The atomic orbital is the wave function that is used to find the probability to find an electron around the nucleus of an atom. It is the space around the nucleus of an atom where the electrons are supposed to be found.
Hybridization is the process of intermixing of atomic orbital of slightly different energies to form hybrid orbitals that have similar energy. These orbital have lower energy and more stability than the atomic orbital.
Hybridization of the central atom can be determined from the number of electron groups around the central atom in the Lewis structure of the molecule. Single bond, double bond, triple bond and lone pair all are considered as single electron group.
(b)
Interpretation:
The orbital in which the lone pairs of nitrogen atom reside is to be determined.
Concept introduction:
The atomic orbital is the wave function that is used to find the probability to find an electron around the nucleus of an atom. It is the space around the nucleus of an atom where the electrons are supposed to be found.
Hybridization is the process of intermixing of atomic orbital of slightly different energies to form hybrid orbitals that have similar energy. These orbital have lower energy and more stability than the atomic orbital.
Hybridization of the central atom can be determined from the number of electron groups around the central atom in the Lewis structure of the molecule. Single bond, double bond, triple bond and lone pair all are considered as single electron group.
(c)
Interpretation:
Whether the hybridization of carbon in
Concept introduction:
Hybridization is the process of intermixing of atomic orbital of slightly different energies to form hybrid orbitals that have similar energy. These orbital have lower energy and more stability than the atomic orbital.
Hybridization of the central atom can be determined from the number of electron groups around the central atom in the Lewis structure of the molecule. Single bond, double bond, triple bond and lone pair all are considered as single electron group.

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Chapter 11 Solutions
CHEMISTRY(LOOSELEAF) W/CONNECT+EBOOK
- Fina x | Sign X Sign X lab: X Intro X Cop) X a chat x My x Grad xLaur x Laur x a sheg X S Shoj XS SHE X acmillanlearning.com/ihub/assessment/f188d950-dd73-11e0-9572-0800200c9a66/d591b3f2-d5f7-4983-843c-0d00c1c0340b/f2b47861-07c4-4d1b-a1ee-e7db27d6b4ee?actualCourseld=d591b3f2- 5 © Macmillan Learning Organic Chemistry Maxwell presented by Macmillan Learning For the dehydrohalogenation (E2) reaction shown, draw the Zaitsev product, showing the stereochemistry clearly. H H KOH Br EtOH Heat Select Draw Templates More Erase // C H Q Search hp Q2 Q Δ קו Resouarrow_forwardIs the structural form shown possible given the pKa constraints of the side chains?arrow_forwardon x Fina X Sign X Sign x lab X Intro X Cop X chat X My x Grac x Laur x Laur x ashes x S Shox S SHE x a eve.macmillanlearning.com/ihub/assessment/f188d950-dd73-11e0-9572-0800200c9a66/d591b3f2-d5f7-4983-843c-0d00c1c0340b/f2b47861-07c4-4d1b-a1ee-e7db27d6b4ee?actualCourseld=d591b3f2-c stions estion. ct each urces. +95 Macmillan Learning Draw the product formed by the reaction of potassium t-butoxide with (15,25)-1-bromo-2-methyl-1-phenylbutane (shown). Clearly show the stereochemistry of the product. H BH (CH3)3CO-K+ +100 H3CW (CH3)3COH +85 H3CH2C +95 ossible ↓ Q Search Select Draw Templates More C H 0 bp A Erase 2Q 112 Resouarrow_forward
- Identify the structure of the PTH derivative generated after two rounds of Edman degradation.arrow_forwardUse the data below from an electron impact mass spectrum of a pure compound to deduce its structure. Draw your structure in the drawing window. Data selected from the NIST WebBook, https://webbook.nist.gov/chemistry/ m/z Relative intensity 31 0.5 30 26 29 22 28 100 27 33 26 23 15 4 • You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one. 妊 n ? Previous Nextarrow_forwardfor this question. Write the molecular formula for a compound with the possible elements C, H, N and O that exhibits a molecular ion at M+ = 98.1106. Exact Masses of the Most Abundant Isotope of Selected Elements Isotope Natural abundance (%) Exact mass 1H 99.985 1.008 12C 98.90 12.000 14N 99.63 14.003 160 99.76 15.995 Molecular formula (In the order CHNO, with no subscripts)arrow_forward
- PLEASE READ!!! I DONT WANT EXAMPLES, I DONT WANT WORDS OR PARAGRAPHS!!! PLEASE I UNDERSTAND THE BASICS BUT THIS IS AN EXCEPTION THAT EVEN THE INTERNET CANT HELP!!!! THIS IS THE THIRD TIME I'VE SENT THOSE QUESTIONS SO PLEASE DONT RESEND THE SAME STUFF, ITS NOT HELPING ME!!! I ALSO ALREADY TRIED TO DRAW THE MECHANISM MYSELF, SO IF ITS RIGHT PLEASE TELL ME OR TELL ME WHAT I HAVE TO CHANGE!!! First image: I have to SHOW (DRAWING) the mechanism (with arows and structures of molecules) NOT WORDS PLEASE! of the reaction at the bottom. Also I have to show by mecanism why the reaction wouldn't work if the alcohol was primary Second image: I have to show the mechanism (IMAGE) (with arrows and structures of the molecules) NOT WORDS PLEASE !! for the reaction on the left, where the alcohol A is added fast in one portion HOMEWORK, NOT EXAM!! ALL DETAILS ARE IN THE IMAGES PLEASE LOOK AT THE IMAGES, DONT LOOK AT THE AI GENERATED TEXT!!!arrow_forwardWrite the molecular formula for a compound with the possible elements C, H, N and O that exhibits a molecular ion at M+ = 85.0899. Exact Masses of the Most Abundant Isotope of Selected Elements Isotope Natural abundance (%) Exact mass 1H 99.985 1.008 12C 98.90 12.000 14N 99.63 14.003 160 99.76 15.995 Molecular formula (In the order CHNO, with no subscripts)arrow_forwardUse the data below from an electron impact mass spectrum of a pure compound to deduce its structure. Draw your structure in the drawing window. Data selected from the NIST WebBook, https://webbook.nist.gov/chemistry/ m/z Relative intensity 59 3.0 58 64 43 100 15 23 • You do not have to consider stereochemistry. •You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one. + n[] 85 // ? CH4 Previous Nextarrow_forward
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