Chapter 11, Problem 11.50QP

Interpretation Introduction

Interpretation:

The vapour pressure of Methanol at $\text{22°C}$ is to be calculated.

Concept introduction:

Clausius - Clapeyron equation:

This equation is relation between heat of vaporization and pressure at definite temperature.

$\text{ln}\frac{{\text{P}}_{\text{2}}}{{\text{P}}_{\text{1}}}\text{= -}\frac{{\text{ΔH}}_{\text{vap}}}{\text{R}}\text{(}\frac{\text{1}}{{\text{T}}_{\text{2}}}\text{-}\frac{\text{1}}{{\text{T}}_{\text{1}}}\text{)}$

Where,

${\text{P}}_{\text{1}}$- Vapour pressure at temperature ${\text{T}}_{\text{1}}$

${\text{P}}_2$- Vapour pressure at temperature ${\text{T}}_2$

R- Universal gas constant that is equal to $\text{8}\text{.314 J/mol}\text{.K}$

${\text{ΔH}}_{\text{vap}}$- Enthalpy of vaporization of the substance