Explanation Given data Amount of Nitrogen gas passed = 6 .35 L at 25°C and 768 mmHg Amount of Acetone evaporated = 6 .550g To determine: Vapour pressure of Acetone at 25°C Use ideal gas equation, n = PV RT = (768/760atm)(6 .35L) (0 .082057L•atm/K•mol)(298 .2K) = 0 .2622 mol To determine: Number of mole of Acetone leaving the liquid n = 6 .550g C 3 H 6 O × 1mol C 3 H 6 O 58 .08g C 3 H 6 O = 0

OWLv2 for Ebbing/Gammon's General Chemistry, 11th Edition, [Instant Access], 1 term (6 months)

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ISBN: 9781305673939

Author: Darrell Ebbing; Steven D. Gammon

Publisher: Cengage Learning US

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Chapter 11, Problem 11.150QP

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When 6.550g acetone has evaporated the vapour pressure of Acetone at 25°C has to be determined.

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Chapter 11, Problem 11.149QP

Chapter 11, Problem 11.151QP

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OWLv2 for Ebbing/Gammon's General Chemistry, 11th Edition, [Instant Access], 1 term (6 months)

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When 6 .550g acetone has evaporated the vapour pressure of Acetone at 25°C has to be determined.

Solution Summary: The author explains how the vapour pressure of Acetone at 25°C has to be determined.

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Interpretation:

When 6.550g acetone has evaporated the vapour pressure of Acetone at 25°C has to be determined.

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Chapter 11 Solutions

When 6 .550g acetone has evaporated the vapour pressure of Acetone at 25°C has to be determined.

Solution Summary: The author explains how the vapour pressure of Acetone at 25°C has to be determined.

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Interpretation: When 6.550g acetone has evaporated the vapour pressure of Acetone at 25°C has to be determined.

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Chapter 11 Solutions

Interpretation:

When 6.550g acetone has evaporated the vapour pressure of Acetone at 25°C has to be determined.