EBK SYSTEM DYNAMICS
3rd Edition
ISBN: 8220100254963
Author: Palm
Publisher: MCG
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Chapter 11, Problem 11.4P
Sketch the root locus plot of ms~ 4- 12s + 10 = 0 for in > 2. What is the smallest possible dominant time constant, and what value of m gives this time constant?
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Please solve the following by hand and without the use of AI. I am working to understand the step by step procedure of solving this problem so pleaase give a detailed step by step procedure, explaining each part as you go. Thank you!
Please solve the following by hand and without the use of AI. I am working to understand the step by step procedure of solving this problem so pleaase give a detailed step by step procedure, explaining each part as you go. Thank you!
Q.4- A model for feedback control system employing both angular position
and velocity feedback is shown in figure bellow .The equation describing
d²0
do
di
the system is J
di²
-
=
• K.[V₁-K₁0.
K₂0-Ka
((1)
Summing
V,(r)
Motor
白口食
amplifier
Velocity
sensor
K₂8
Position
sensor
Where J is the rotary inertia KandK are the position and velocity feedback
gains, and K, is the gain between the input voltages to the motor torque
produced. Derive expression for the closed loop system undamped natural
frequency and damping ratio.
Chapter 11 Solutions
EBK SYSTEM DYNAMICS
Ch. 11 - Prob. 11.1PCh. 11 - Prob. 11.2PCh. 11 - Prob. 11.3PCh. 11 - Sketch the root locus plot of ms~ 4- 12s + 10 = 0...Ch. 11 - Prob. 11.5PCh. 11 - Prob. 11.6PCh. 11 - Prob. 11.7PCh. 11 - PID control action is applied to the plant GPU) =...Ch. 11 - Consider the following equation where the...Ch. 11 - 11.10 In the following equation. K > 0.
j2(j+9) +...
Ch. 11 - 11.11 Consider the following equation where the...Ch. 11 - 11.12 In the following equations, identify the...Ch. 11 - Prob. 11.13PCh. 11 - Prob. 11.14PCh. 11 - Prob. 11.15PCh. 11 - Prob. 11.16PCh. 11 - Prob. 11.17PCh. 11 - Prob. 11.18PCh. 11 - Prob. 11.19PCh. 11 - Prob. 11.20PCh. 11 - Prob. 11.21PCh. 11 - Prob. 11.23PCh. 11 - Prob. 11.24PCh. 11 - Prob. 11.25PCh. 11 - Prob. 11.26PCh. 11 - Prob. 11.27PCh. 11 - Prob. 11.28PCh. 11 - Prob. 11.29PCh. 11 - Prob. 11.30PCh. 11 - Prob. 11.32PCh. 11 - Prob. 11.33PCh. 11 - Prob. 11.34PCh. 11 - Prob. 11.35PCh. 11 - The following equations are the model of the roll...Ch. 11 - Prob. 11.38P
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- Sketching Root Locus warm-up (do all by hand): 8.1, 8.2, 8.3 1. For each of the root loci shown in Figure P8.1, tell whether or not the sketch can be a root locus. If the sketch cannot be a root locus, explain why. Give all reasons. [Section: 8.4] s-plane -plane FIGURE P8.1 *O** 8 (a) joe s-plane 3-plane 8 (e) Double pole (d) X-plane × (e) je 8 ja) s-plane 8 (8) s-plane 8 s-planearrow_forwardBelow is an open loop transfer function which is given: A(s) A(s) = = 0.1(s +14) (s+7)(s + 5) Use matlab's bode function and plot its bode diagram. Show the figure Use the following MATLAB script and write a code for bode plotting concerning the open loop transfer function. Clear Close all clc w 0. 1:0.001:100; ns = length (w); for i=1:nS %Write the code here endarrow_forwardPlease help me .. answer my Question , I don't want to quote or plagiarize, don't use your handwriting just use MS Word .arrow_forward
- Match the transfer function with correct Bode phase plots. G(s) = 5 $+7 G(s)=s+5 G(s) = s+10 S S G(s) = S+ 10 QUESTION 10 90 deg 00 0 deg -90 deg 180 deg B. D 90 deg @ 0 deg -90 deg 180 deg 90 deg @ 0 deg -90 deg 180 deg 90 deg @ 0 deg -90 deg 180 degarrow_forward2- Using Matlab, what are the step response curves of the closed-loop system, as shown in fig.1. the feedback represents the second-order dynamic system. (fill in the following table) For=0.4 Wn 1 3 6 9 10 R(S) 0.1 0.3 0.6 0.9 1 For w 5 rad/sec 3 Settling time Peak response 2 Wn s(s+23wn) Settling time Peak response C(s) Discuss the follow Which parameters or w occur on the rise time of the response? Which parameter increases the speed of response? Which parameters can be decreases the response amplitude? Which parameter decreases the steady error state? fig.2arrow_forwardPleasearrow_forward
- Given the trasnfer function G(s) numerator and denominator coefficients for Matlab code should be: O s³+2s+1 2s4+2s²+1' the num= [1 0 2 1] and den=[2 020 1] O num=[1 2 1] and den=[2 0 2 1 1] O num=[1 2 1] and den=[2 2 1] O num=[1 0 2 1] and den=[2 2 0 1]arrow_forward10- To enter the transfer functions G(s)= a) G= th(2, [3,2]) b) c) d) G(s) TH (2, [2, 3]) G= tf (2, [3,2]) G(s)= TF(2, [2, 3]) 2 3s+2 c) A marginally stable response d) A marginally unstable response to Matlab command use: 3s+1 11- To enter the transfer function g(s)= $2+35+2 ,can be use a) num=[3, 1]; den= [1, 3, 2]; g-tf (den, num) num=[3, 1]; den=[1, 3, 2]; g=tf (num, den) b) c) num=[3; 1]; den=[1, 3, 2]; g=tf (den, num) d) num=(3, 1); den=(1, 3; 2); g-tf (num, den) 12- What is the output of the code (>>p=[0 1]; q=[ 1 -1 0]; step(p,q) ) a) An unstable response b) A stable response (s+1)arrow_forwardFigure 1 shows a six degree of freedom industrial robot. i. Construct the coordinates frames based on the D-H representations. ii. Complete the D-H parameter as illustrated in Table 1.arrow_forward
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