Loose Leaf For Introduction To Chemical Engineering Thermodynamics
8th Edition
ISBN: 9781259878084
Author: Smith Termodinamica En Ingenieria Quimica, J.m.; Van Ness, Hendrick C; Abbott, Michael; Swihart, Mark
Publisher: McGraw-Hill Education
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Chapter 11, Problem 11.31P
Interpretation Introduction
Interpretation:
To find the heat effect per mole of NaOH neutralized.
Concept Introduction:
First we find heat of formation of NaCl, NaOH and HCl. Then we find the heat of individual reactions.
The reaction is as given below,
NaOH(s) + HCl(g) → NaCl(s) + H2O (l)
The heat effect, Q is found for the reaction,
NaOH.8 H2O + HCl.9 H2O → NaCl.8 H2O
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Chapter 11 Solutions
Loose Leaf For Introduction To Chemical Engineering Thermodynamics
Ch. 11 - Prob. 11.1PCh. 11 - Prob. 11.2PCh. 11 - Prob. 11.3PCh. 11 - Prob. 11.4PCh. 11 - Prob. 11.5PCh. 11 - Prob. 11.6PCh. 11 - Prob. 11.7PCh. 11 - Prob. 11.8PCh. 11 - Prob. 11.9PCh. 11 - Prob. 11.10P
Ch. 11 - Prob. 11.11PCh. 11 - Prob. 11.12PCh. 11 - Prob. 11.13PCh. 11 - Prob. 11.14PCh. 11 - Prob. 11.15PCh. 11 - Prob. 11.16PCh. 11 - Prob. 11.17PCh. 11 - Prob. 11.18PCh. 11 - Prob. 11.19PCh. 11 - Prob. 11.20PCh. 11 - Prob. 11.21PCh. 11 - Prob. 11.22PCh. 11 - Prob. 11.23PCh. 11 - Prob. 11.24PCh. 11 - Prob. 11.25PCh. 11 - Prob. 11.26PCh. 11 - Prob. 11.27PCh. 11 - Prob. 11.28PCh. 11 - Prob. 11.29PCh. 11 - Prob. 11.30PCh. 11 - Prob. 11.31PCh. 11 - Prob. 11.32PCh. 11 - Prob. 11.33PCh. 11 - Prob. 11.34PCh. 11 - Prob. 11.35PCh. 11 - Prob. 11.36P
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