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Repeat Problem 11.1 based on limit state design, using the factors given in Table 11.4.
11.1 A continuous foundation is required in a soil where
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Principles of Foundation Engineering
- Consider a continuous foundation of width B = 1.4 m on a sand deposit with c = 0, = 38, and = 17.5 kN/m3. The foundation is subjected to an eccentrically inclined load (see Figure 6.33). Given: load eccentricity e = 0.15 m, Df = 1 m, and load inclination = 18. Estimate the failure load Qu(ei) per unit length of the foundation a. for a partially compensated type of loading [Eq. (6.89)] b. for a reinforced type of loading [Eq. (6.90)]arrow_forwardA 2.0 m wide continuous foundation carries a wall load of 350 kN/m in a clayey soil where = 19.0 kN/m3, c = 5.0 kN/m2, and = 23. The foundation depth is 1.5 m. Determine the factor of safety of this foundation using Eq. (6.28).arrow_forwardUse Terzaghi's equation and Terzaghi's Tablearrow_forward
- A column foundation is 3 m × 2 m in plan. Given: Dƒ = 1.5 m, þ' = 30°, c′ = 80 kN/m². Using the general bearing capacity equation (CFEM see class slides from March 17 similar to Example 1 and 2 but with an added capacity term related to cohesion) and 0.5, determine the factored bearing capacity of the foundation (i.e. – use Þ). Use Yw = 9.81 kN/m³. For simplicity, read the values of Nc, Ną, and Ny directly from the table on page 26 of the lecture slides use the highlighted columns. Also, determine the maximum factored load for the column. - 1.5 m ↑ 1 m 3m x 2m - y = 17 kN/m³ Groundwater level Ysat = 19.5 kN/m³ =arrow_forwardPrinciples Of Foundation Engineering 9e 9th Edition, Das Ch7 problem 7.8arrow_forwardR1arrow_forward
- No diagram. Just this informationarrow_forwardA 1.70 m by 2.60 m footing has its base 1.70 m below the ground surface. GWT is a meter above its base. (L along x-axis) Y = 15.75 kN/m C= 15 kPa Yut = 19 kN/m =26° Using Meyerhof's formula, determine the net ultimate load that the footing could carry if e = 0.45 m and es = 0.30 m. PLEASE MAKE YOUR HANDWRITING READABLE AND CLEAR. THANK YOU SO MUCH :)arrow_forwardb. Ultimate soil bearing capacity, qu (in kN/m2) qu = c. Allowable soil bearing capacity, qall (in kN/m2) if factor of safety is 3.0 qall = Thank youarrow_forward
- c. Allowable soil bearing capacity, qall (in kN/m2) if factor of safety is 3.0 qall = Thank youarrow_forward2. A medium dense sand is proposed to support a square foundation having a width and length of 5 feet as shown below. The bottom of the footing is 2.5 feet below the ground surface. The water table is 4 feet below the bottom of the footing. Using a factor of safety of 3, what is the allowable bearing capacity of the proposed footing? Gs= 2.6 e = 0.5 Ø = 35° 5 ft d = 4 ftarrow_forwardPlease see attached picture.arrow_forward
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