EBK ORGANIC CHEMISTRY: PRINCIPLES AND M
EBK ORGANIC CHEMISTRY: PRINCIPLES AND M
2nd Edition
ISBN: 9780393630817
Author: KARTY
Publisher: W.W.NORTON+CO. (CC)
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Chapter 11, Problem 11.27P
Interpretation Introduction

(a)

Interpretation:

The reaction and complete, detailed mechanism for the reaction is to be drawn.

Concept introduction:

Alkyl halide is the product of the electrophilic addition reaction of the alkene with a strong Bronsted acid such as HCl or HBr.

A strong Bronsted acid such as HCl or HBr has an electron poor proton, which is an electrophile. These acids can therefore react with the nonpolar π bond of an alkene, which is relatively electron rich. An electrophilic addition reaction takes place, in which the Bronsted acid adds across a C=C double bond in two steps. In the first step, the proton adds to one carbon followed by the coordination of halide anion.

Expert Solution
Check Mark

Answer to Problem 11.27P

The overall reaction for the given compound is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 11, Problem 11.27P , additional homework tip  1

The complete mechanism for the above reaction is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 11, Problem 11.27P , additional homework tip  2

Explanation of Solution

The structure for the given compound 4-chloro-1, 2-dimethylcyclohexane is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 11, Problem 11.27P , additional homework tip  3

The compound shown above is the alkyl halide compound. This compound is formed by an electrophilic addition reaction of alkene with a strong Bronsted acid HCl, followed by the coordination of halide anion.

The overall reaction for the given compound is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 11, Problem 11.27P , additional homework tip  4

The above reaction completes in two steps. In the first step, the electrophilic addition step, the proton is added to one carbon with C=C bond, forming the carbocation intermediate. The second step is the coordination step in which the nucleophile attacks the carbocation to yield the product.

The complete mechanism for the above reaction is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 11, Problem 11.27P , additional homework tip  5

Conclusion

The reaction and complete, detailed mechanism for the reaction is drawn on the basis of the mechanism of electrophilic addition reaction of alkenes with strong acid.

Interpretation Introduction

(b)

Interpretation:

The reaction and complete, detailed mechanism for the reaction is to be drawn.

Concept introduction:

Alkyl halide is the product of the electrophilic addition reaction of the alkene with a strong Bronsted acid such as HCl or HBr.

A strong Bronsted acid such as HCl or HBr has an electron poor proton, which is an electrophile. These acids can therefore react with the nonpolar π bond of an alkene, which is relatively electron rich. An electrophilic addition reaction takes place, in which the Bronsted acid adds across a C=C double bond in two steps. In the first step, the proton adds to one carbon followed by the coordination of halide anion.

Expert Solution
Check Mark

Answer to Problem 11.27P

The overall reaction for the given compound is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 11, Problem 11.27P , additional homework tip  6

The complete mechanism for the above reaction is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 11, Problem 11.27P , additional homework tip  7

Explanation of Solution

The structure for the given compound 1-chloro-1, 2-dimethylcyclohexane is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 11, Problem 11.27P , additional homework tip  8

The compound shown above is the alkyl halide compound. This compound is formed by an electrophilic addition reaction of an alkene with a strong Bronsted acid HCl followed by the coordination of halide anion.

The overall reaction for the given compound is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 11, Problem 11.27P , additional homework tip  9

The above reaction completes in two steps. In the first step, the electrophilic addition step, the proton is added to one carbon with C=C bond, forming the carbocation intermediate. The second step is the coordination step in which the nucleophile attacks the carbocation to yield the product.

The complete mechanism for the above reaction is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 11, Problem 11.27P , additional homework tip  10

Conclusion

The reaction and complete, detailed mechanism for the reaction is drawn on the basis of the mechanism of electrophilic addition reaction of alkenes with strong acid.

Interpretation Introduction

(c)

Interpretation:

The reaction and complete, detailed mechanism for the reaction is to be drawn.

Concept introduction:

Alkyl halide is the product of the electrophilic addition reaction of the alkene with a strong Bronsted acid such as HCl or HBr.

A strong Bronsted acid such as HCl or HBr has an electron poor proton, which is an electrophile. These acids can therefore react with the nonpolar π bond of an alkene, which is relatively electron rich. An electrophilic addition reaction takes place, in which the Bronsted acid adds across a C=C double bond in two steps. In the first step, the proton adds to one carbon followed by the coordination of halide anion.

Expert Solution
Check Mark

Answer to Problem 11.27P

The overall reaction for the given compound is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 11, Problem 11.27P , additional homework tip  11

The complete mechanism for the above reaction is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 11, Problem 11.27P , additional homework tip  12

Explanation of Solution

The structure for the given compound 1-bromo-1, 1-diphenylbutane is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 11, Problem 11.27P , additional homework tip  13

The compound shown above is the alkyl halide compound. This compound is formed by an electrophilic addition reaction of alkene with a strong Bronsted acid HCl, followed by the coordination of halide anion.

The overall reaction for the given compound is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 11, Problem 11.27P , additional homework tip  14

The above reaction completes in two steps. In the first step, the electrophilic addition step, the proton added to the internal carbon, forming the the more stable carbocation intermediate, which is tertiary and resonance stabilized. The second step is the coordination step in which the nucleophile attacks the carbocation to yield the product.

The complete mechanism for the above reaction is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 11, Problem 11.27P , additional homework tip  15

Conclusion

The reaction and complete, detailed mechanism for the reaction is drawn on the basis of the mechanism of electrophilic addition reaction of alkenes with strong acid.

Interpretation Introduction

(d)

Interpretation:

The reaction and complete, detailed mechanism for the reaction is to be drawn.

Concept introduction:

Alkyl halide is the product of the electrophilic addition reaction of the alkene with a strong Bronsted acid such as HCl or HBr.

A strong Bronsted acid such as HCl or HBr has an electron poor proton, which is an electrophile. These acids can therefore react with the nonpolar π bond of an alkene, which is relatively electron rich. An electrophilic addition reaction takes place, in which the Bronsted acid adds across a C=C double bond in two steps. In the first step, the proton adds to one carbon followed by the coordination of halide anion.

Expert Solution
Check Mark

Answer to Problem 11.27P

The overall reaction for the given compound is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 11, Problem 11.27P , additional homework tip  16

The complete mechanism for the above reaction is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 11, Problem 11.27P , additional homework tip  17

Explanation of Solution

The structure for the given compound 2, 2-dichloropentane is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 11, Problem 11.27P , additional homework tip  18

The compound shown above is the alkyl halide compound. This compound is formed by an electrophilic addition reaction of alkene with a strong Bronsted acid HCl, followed by the coordination of halide anion.

The overall reaction for the given compound is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 11, Problem 11.27P , additional homework tip  19

The above reaction completes in two steps. In the first step, the electrophilic addition step, the proton is added to the internal carbon, forming the the more stable carbocation intermediate, which is tertiary. The second step is the coordination step in which the nucleophile attacks the carbocation to yield the product.

The complete mechanism for the above reaction is

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 11, Problem 11.27P , additional homework tip  20

Conclusion

The reaction and complete, detailed mechanism for the reaction is drawn on the basis of the mechanism of electrophilic addition reaction of alkenes with strong acid.

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Chapter 11 Solutions

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M

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