Chapter 11, Problem 11.26P

Interpretation Introduction

Interpretation:

To find the final temperature of the solution

Concept Introduction:

We find the Excess enthalpy of pure H₂SO₄from the H-x diagram of H₂SO₄

Then we find the enthalpy of Pure water.

The heat of mixing is as given below,

  $Q=H_3-x_2{H}_2-x_1{H}_1$ =0

Where,

Mass fraction of H₂O= x₁

Mass fraction of H₂SO₄= x₂

Initial Temperature = T₁

Enthalpy of Pure H₂O = H₁ Enthalpy of Pure H₂SO₄ (100-wt-%) = H₂ Enthalpy of 40-wt-% aqueous solution of H₂SO₄ = H₃