Chapter 10.9, Problem 5PSA

a)

To determine

To find : Perimeter of the given figure.

Answer to Problem 5PSA

  $6\pi +40$

Explanation of Solution

Given Information :

  

As given in figure

Radius = $3$ and side of square = $10$

Formula Used:

Perimeter of $\frac{1}{2}$ semi-circle $=\frac{\pi r}{2}$

Perimeter of square = $4$ × side

Calculation :

Perimeter of given figure

  $\begin{array}{l}=4\left(\frac{\pi r}{2}\right)+4(10)\\ =2\pi r+40\\ =6\pi +40\end{array}$

b)

To determine

To find : Perimeter of the given figure.

Answer to Problem 5PSA

  $4\pi +24$

Explanation of Solution

Given Information :

  

The given information is radius = $4$ and side of square = $8$

Formula Used:

Circumference of circle = $\pi r$

Perimeter of square = $4$ × side

Calculation :

Perimeter of given figure $=\pi r+8(3)=4\pi +24$

c)

To determine

To find : Perimeter of the given figure.

Answer to Problem 5PSA

  $3\pi +12$

Explanation of Solution

Given Information :

  

The given information is Side of triangle = $6$ , Radius = $3$

Formula Used:

Circumference of circle = $2\pi r$

Calculation :

Perimeter of given figure = $\pi r+6(2)=3\pi +12$

d)

To determine

To find : Perimeter of the given figure.

Answer to Problem 5PSA

  $7\pi +6$

Explanation of Solution

Given Information :

The given information is Radius = 6

  

Formula Used:

Circumference of circle = $2\pi r$

Calculation :

Perimeter of given figure

  $\begin{array}{l}=\left(\frac{4\pi }{2}\right)+\left(\frac{10\pi }{2}\right)+6\\ =7\pi +6\end{array}$