Using MIS (9th Edition)
9th Edition
ISBN: 9780134106786
Author: David M. Kroenke, Randall J. Boyle
Publisher: PEARSON
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Expert Solution & Answer
Chapter 10.9, Problem 10.9ARQ
Explanation of Solution
The opinion of authors regarding cyberwarfare in the next 10 years:
Cyberwarfare is a technical conflict with national disaster. According to authors, human errors and natural disaster errors are constant. Because, human error cannot be changed and natural disaster never estimated.
Most organization will set up their sites and data’s in well-prepared clouds. Other than human error and natural disaster there will be threat is known as APT (Advanced Persistent Threat).
- Note: APT is a network attack from unauthorized person for long time. The goal of APT is damage the network of the organization.
- In author point of view, there is some new APT’s can affected on organization that will cause a serious damage.
Cat and mouse:
Hackers search the vulnerability to attack an organization and they exploit it.
- Experts of
computer security provide the safeguard then the hackers find the new type of vulnerability and experts exploit it. - This type of process looks like a cat and mouse in computer crime evaluation.
- For the next ten year, it will be continued as cat and mouse game...
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Exercise 1 Function and Structure [30 pts]
Please debug the following program and answer the following questions. There is a cycle in a linked
list if some node in the list can be reached again by continuously following the next pointer.
#include
typedef struct node {
int value;
struct node *next;
} node;
int 11_has_cycle (node *first)
if (first
==
node *head =
{
NULL) return 0;
first;
while (head->next != NULL) {
}
if (head
first) {
return 1; }
head = head->next;
return 0;
void test ll_has_cycle () {
int i;
node nodes [6];
for (i = 0; i < 6; i++) {
nodes [i] .next = NULL;
nodes [i].value = i;
}
nodes [0] .next
=
&nodes [1];
nodes [1] .next
=
&nodes [2];
nodes [2] .next
=
&nodes [3];
nodes [3] .next
nodes [4] .next
&nodes [4];
NULL;
nodes [5] .next = &nodes [0];
printf("1. Checking first list for cycles. \n Function 11_has_cycle says it
has s cycle\n\n", 11_has_cycle (&nodes [0])?"a":"no");
printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle
says it has %s…
Chapter 10 Solutions
Using MIS (9th Edition)
Ch. 10.4 - Prob. 1NFBHCh. 10.4 - Prob. 2NFBHCh. 10.4 - Prob. 3NFBHCh. 10.4 - Prob. 4NFBHCh. 10.4 - Prob. 5NFBHCh. 10.5 - Prob. 1EGDQCh. 10.5 - Prob. 2EGDQCh. 10.5 - Prob. 3EGDQCh. 10.5 - Prob. 4EGDQCh. 10.5 - Prob. 5EGDQ
Ch. 10.5 - Prob. 6EGDQCh. 10.5 - Prob. 7EGDQCh. 10.9 - Prob. 1SGDQCh. 10.9 - Prob. 2SGDQCh. 10.9 - Prob. 3SGDQCh. 10.9 - Prob. 4SGDQCh. 10.9 - Prob. 5SGDQCh. 10.9 - Prob. 1PCIBCh. 10.9 - Prob. 2PCIBCh. 10.9 - Prob. 3PCIBCh. 10.9 - Prob. 4PCIBCh. 10.9 - Prob. 5PCIBCh. 10.9 - Prob. 10.1ARQCh. 10.9 - Prob. 10.2ARQCh. 10.9 - Prob. 10.3ARQCh. 10.9 - Prob. 10.4ARQCh. 10.9 - Prob. 10.5ARQCh. 10.9 - Prob. 10.6ARQCh. 10.9 - Prob. 10.7ARQCh. 10.9 - Prob. 10.8ARQCh. 10.9 - Prob. 10.9ARQCh. 10 - Prob. 10.1UYKCh. 10 - Prob. 10.2UYKCh. 10 - Prob. 10.3UYKCh. 10 - Prob. 10.4CE10Ch. 10 - Prob. 10.5CE10Ch. 10 - Prob. 10.6CE10Ch. 10 - Prob. 10.7CE10Ch. 10 - Prob. 10.8CS10Ch. 10 - Prob. 10.9CS10Ch. 10 - Prob. 10.10CS10Ch. 10 - Prob. 10.11CS10Ch. 10 - Prob. 10.12CS10Ch. 10 - Prob. 10.13CS10Ch. 10 - Prob. 10.14CS10Ch. 10 - Prob. 10.15MMLCh. 10 - Prob. 10.16MML
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