Engineering Mechanics: Statics and Study Pack (13th Edition)
13th Edition
ISBN: 9780133027990
Author: Russell C. Hibbeler
Publisher: Prentice Hall
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Chapter 10.8, Problem 116RP
Determine the moment of inertia for the shaded area about the x axis.
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CORRECT AND DETAILED HANDWRITTEN SOLUTION WITH FBD ONLY. I WILL UPVOTE THANK YOU. CORRECT ANSWER IS ALREADY PROVIDED.
12: A steel cantilever beam 16 ft 8 in in length is subjected to a concentrated load of 320 lb acting at the freeend of the bar. A commercially available rolled steel section, designated as W12x32, is used for the beam. Assume that the total depth of the beam is 12 in, and the neutral axis of the section is in the middle. Determine the maximum tensile and compressive stresses. (Properties of commercially available rolled steel section provided in the table. Z = section modulus). ANS: σT = σC = 1,572.482 lb/in2
CORRECT AND DETAILED HANDWRITTEN SOLUTION WITH FBD ONLY. I WILL UPVOTE THANK YOU. CORRECT ANSWER IS ALREADY PROVIDED.
14: Two ½-in x 8-in cover plates are welded to two channels 10 in high to formthe cross section of the beam shown in Fig. 8-59. Loads are in a vertical plane and bendingtakes place about a horizontal axis. The moment of inertia of each channel about ahorizontal axis through the centroid is 78.5 in4. If the maximum allowable elastic bendingstress is 18,000 lb/in2, determine the maximum bending moment that may be developedin the beam.ANS: 1,236,000 lb-in.
CORRECT AND DETAILED HANDWRITTEN SOLUTION WITH FBD ONLY. I WILL UPVOTE THANK YOU. CORRECT ANSWER IS ALREADY PROVIDED.
11: A beam of circular cross section is 7 in in diameter. It is simply supported at each end and loaded by twoconcentrated loads of 20,000 lb each, applied 12 in from the ends of the beam. Determine the maximum bending stressin the beam. ANS: σ = 7,127.172 lb/in2
Chapter 10 Solutions
Engineering Mechanics: Statics and Study Pack (13th Edition)
Ch. 10.3 - Determine the moment of inertia of the shaded area...Ch. 10.3 - Determine the moment of inertia of the shaded area...Ch. 10.3 - Determine the moment of inertia of the shaded area...Ch. 10.3 - Determine the moment of inertia of the shaded area...Ch. 10.3 - Prob. 1PCh. 10.3 - Prob. 2PCh. 10.3 - Prob. 3PCh. 10.3 - Prob. 4PCh. 10.3 - Prob. 5PCh. 10.3 - Prob. 6P
Ch. 10.3 - Prob. 7PCh. 10.3 - Prob. 8PCh. 10.3 - Determine the moment of inertia of the area about...Ch. 10.3 - Solve the problem in two ways, using rectangular...Ch. 10.3 - Prob. 11PCh. 10.3 - Prob. 12PCh. 10.3 - Prob. 13PCh. 10.3 - Prob. 14PCh. 10.3 - Prob. 15PCh. 10.3 - Prob. 16PCh. 10.3 - Prob. 17PCh. 10.3 - Prob. 18PCh. 10.3 - Prob. 19PCh. 10.3 - Prob. 20PCh. 10.3 - Prob. 21PCh. 10.3 - Prob. 22PCh. 10.3 - Prob. 23PCh. 10.3 - Prob. 24PCh. 10.4 - Determine the moment of inertia of the beams...Ch. 10.4 - Determine the moment of inertia of the beams...Ch. 10.4 - Determine me moment of inertia of the...Ch. 10.4 - Determine the moment of inertia of the...Ch. 10.4 - Determine the moment of inertia of the composite...Ch. 10.4 - Determine the moment of inertia of the composite...Ch. 10.4 - Prob. 27PCh. 10.4 - Prob. 28PCh. 10.4 - Prob. 29PCh. 10.4 - Prob. 30PCh. 10.4 - Prob. 31PCh. 10.4 - Prob. 32PCh. 10.4 - Prob. 33PCh. 10.4 - Determine the moment of inertia of the beams...Ch. 10.4 - Determine, g, which locates the centroidal axis z...Ch. 10.4 - Prob. 36PCh. 10.4 - Prob. 37PCh. 10.4 - Prob. 38PCh. 10.4 - Prob. 39PCh. 10.4 - Prob. 41PCh. 10.4 - Determine the moment of inertia of the beams...Ch. 10.4 - Prob. 43PCh. 10.4 - Prob. 44PCh. 10.4 - Determine the distance x to the centroid C of the...Ch. 10.4 - Determine the moment of inertia of the area about...Ch. 10.4 - Determine the moment of inertia of the area about...Ch. 10.4 - Prob. 50PCh. 10.4 - Prob. 51PCh. 10.4 - Determine the moment of inertia of the...Ch. 10.4 - Determine the moment of inertia of the...Ch. 10.7 - Determine the product of inertia of the thin strip...Ch. 10.7 - Prob. 55PCh. 10.7 - Determine the product of inertia of the shaded...Ch. 10.7 - Prob. 57PCh. 10.7 - Determine the product of inertia of the shaded...Ch. 10.7 - Prob. 59PCh. 10.7 - Prob. 60PCh. 10.7 - Prob. 62PCh. 10.7 - Determine the product of inertia for the beams...Ch. 10.7 - Prob. 64PCh. 10.7 - Prob. 65PCh. 10.7 - Determine the product of inertia of the cross...Ch. 10.7 - Prob. 67PCh. 10.7 - For the calculation, assume all comers to be...Ch. 10.7 - Prob. 69PCh. 10.7 - Prob. 70PCh. 10.7 - Prob. 71PCh. 10.7 - Prob. 72PCh. 10.7 - Prob. 73PCh. 10.7 - Prob. 74PCh. 10.7 - Prob. 75PCh. 10.7 - Prob. 76PCh. 10.7 - Prob. 77PCh. 10.7 - Prob. 78PCh. 10.7 - Prob. 79PCh. 10.7 - Prob. 80PCh. 10.7 - Prob. 81PCh. 10.7 - Prob. 82PCh. 10.7 - using Mohrs circle.Ch. 10.8 - Determine the moment of inertia of the thin ring...Ch. 10.8 - The material has a constant density .Ch. 10.8 - Prob. 86PCh. 10.8 - Determine the radius of gyration kx of the...Ch. 10.8 - The material has a constant density .Ch. 10.8 - Hint: For integration, use thin plate elements...Ch. 10.8 - Prob. 90PCh. 10.8 - Prob. 91PCh. 10.8 - Determine the moment of inertia Iy. The specific...Ch. 10.8 - Prob. 93PCh. 10.8 - The total mass of the solid is 1500 kg.Ch. 10.8 - Prob. 95PCh. 10.8 - Prob. 96PCh. 10.8 - Determine the location y of the center of mass G...Ch. 10.8 - Prob. 98PCh. 10.8 - 15 lb. and 20 lb, respectively, determine the mass...Ch. 10.8 - The density of the material is 7.85 Mg/m3.Ch. 10.8 - The material has a density of 200kg/m3. Prob....Ch. 10.8 - The pendulum consists of a plate having a weight...Ch. 10.8 - Prob. 103PCh. 10.8 - The material has a density of 200kg/m3.Ch. 10.8 - Prob. 105PCh. 10.8 - Determine its mass moment of inertia about the y...Ch. 10.8 - Prob. 107PCh. 10.8 - Prob. 108PCh. 10.8 - Prob. 109PCh. 10.8 - Determine the moment of inertia for the shaded...Ch. 10.8 - Prob. 111RPCh. 10.8 - Determine the product of inertia of the shaded...Ch. 10.8 - Determine the area moment of inertia of the...Ch. 10.8 - Determine the area moment of inertia of the shaded...Ch. 10.8 - Determine the moment of inertia for the shaded...Ch. 10.8 - Prob. 117RPCh. 10.8 - Prob. 119RP
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moment of inertia; Author: NCERT OFFICIAL;https://www.youtube.com/watch?v=A4KhJYrt4-s;License: Standard YouTube License, CC-BY