Algebra and Trigonometry: Structure and Method, Book 2
Algebra and Trigonometry: Structure and Method, Book 2
2000th Edition
ISBN: 9780395977255
Author: MCDOUGAL LITTEL
Publisher: McDougal Littell
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Unitary Method
The word “unitary” comes from the word “unit”, which means a single and complete entity. In this method, we find the value of a unit product from the given number of products, and then we solve for the other number of products.
Speed, Time, and Distance
Imagine you and 3 of your friends are planning to go to the playground at 6 in the evening. Your house is one mile away from the playground and one of your friends named Jim must start at 5 pm to reach the playground by walk. The other two friends are 3 …
Profit and Loss
The amount earned or lost on the sale of one or more items is referred to as the profit or loss on that item.
Units and Measurements
Measurements and comparisons are the foundation of science and engineering. We, therefore, need rules that tell us how things are measured and compared. For these measurements and comparisons, we perform certain experiments, and we will need the experime…
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Chapter 10.7, Problem 2P

a.

To determine

To solve.

a.

Expert Solution
Check Mark

Answer to Problem 2P

$107.2

Explanation of Solution

Given information:

One hundred dollars is invested at 7.2% interest compounded annually. We have to determine worth after 1 year.

We shall use the formula for compound interest.

  A=P(1+rn)nt

Where A is the amount and P is principal and ris rate compounded n times.

Worth after 1 year is,

  A=100(1+0.072)1=$107.2

b.

To determine

To solve.

b.

Expert Solution
Check Mark

Answer to Problem 2P

$141.57

Explanation of Solution

Given information:

One hundred dollars is invested at 7.2% interest compounded annually. We have to determine worth after 5 year.

We shall use the formula for compound interest.

Where A is the amount and P is principal and ris rate compounded n times.

Worth after 5 year is,

  A=100(1+0.072)5=$141.57

c.

To determine

To solve.

c.

Expert Solution
Check Mark

Answer to Problem 2P

$200.42

Explanation of Solution

Given information:

One hundred dollars is invested at 7.2% interest compounded annually. We have to determine worth after 10 year.

We shall use the formula for compound interest.

  A=P(1+rn)nt

Where A is the amount and P is principal and ris rate compounded n times.

Worth after 10 year is,

  A=1000(1+0.12)10=$200.42

d.

To determine

To solve.

d.

Expert Solution
Check Mark

Answer to Problem 2P

$401.70

Explanation of Solution

Given information:

one hundred dollars is invested at 7.2% interest compounded annually. Wehave to determine worth after 20 year.

We shall use the formula for compound interest.

Where A is the amount and P is principal and ris rate compounded n times.

Worth after 20 year is,

  A=1000(1+0.072)20=$401.70

e.

To determine

Using the answers from above parts we have to estimate doubling time for the investment.

e.

Expert Solution
Check Mark

Answer to Problem 2P

Doubling time is 10 years on a rate of 7.2% compounded annually.

Explanation of Solution

Doubling rate is given by formula,

  N=N0⋅21d

Where N is present value, N0 is starting value and d is doubling rate.

We have to solve for d

Now we put N=2N0 and take log both sides in order to derive expression for time to double.

Hence we get,

  d=ln(2)ln(1+r100)≈72r

Sometimes this is directly used to calculate the doubling time when the interest is compounded annually. (Called rule of 72)

Hence doubling time is 727.2=10 years.

Previous
Chapter 10.7, Problem 1P
Next
Chapter 10.7, Problem 3P

Chapter 10 Solutions

Algebra and Trigonometry: Structure and Method, Book 2

Ch. 10.1 - Prob. 1OECh. 10.1 - Prob. 2OECh. 10.1 - Prob. 3OECh. 10.1 - Prob. 4OECh. 10.1 - Prob. 5OECh. 10.1 - Prob. 6OECh. 10.1 - Prob. 7OECh. 10.1 - Prob. 8OECh. 10.1 - Prob. 9OECh. 10.1 - Prob. 10OE
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Prob. 12WECh. 10.3 - Prob. 13WECh. 10.3 - Prob. 14WECh. 10.3 - Prob. 15WECh. 10.3 - Prob. 16WECh. 10.3 - Prob. 17WECh. 10.3 - Prob. 18WECh. 10.3 - Prob. 19WECh. 10.3 - Prob. 20WECh. 10.3 - Prob. 21WECh. 10.3 - Prob. 22WECh. 10.3 - Prob. 23WECh. 10.3 - Prob. 24WECh. 10.3 - Prob. 25WECh. 10.3 - Prob. 26WECh. 10.3 - Prob. 1MRECh. 10.3 - Prob. 2MRECh. 10.3 - Prob. 3MRECh. 10.3 - Prob. 4MRECh. 10.3 - Prob. 5MRECh. 10.3 - Prob. 6MRECh. 10.3 - Prob. 7MRECh. 10.3 - Prob. 8MRECh. 10.3 - Prob. 9MRECh. 10.3 - Prob. 10MRECh. 10.3 - Prob. 11MRECh. 10.3 - Prob. 12MRECh. 10.3 - Prob. 1STCh. 10.3 - Prob. 2STCh. 10.3 - Prob. 3STCh. 10.3 - Prob. 4STCh. 10.3 - Prob. 5STCh. 10.3 - Prob. 6STCh. 10.3 - Prob. 7STCh. 10.4 - Prob. 1OECh. 10.4 - Prob. 2OECh. 10.4 - Prob. 3OECh. 10.4 - Prob. 4OECh. 10.4 - Prob. 5OECh. 10.4 - Prob. 6OECh. 10.4 - Prob. 7OECh. 10.4 - Prob. 8OECh. 10.4 - Prob. 9OECh. 10.4 - Prob. 10OECh. 10.4 - Prob. 11OECh. 10.4 - Prob. 12OECh. 10.4 - Prob. 13OECh. 10.4 - Prob. 14OECh. 10.4 - Prob. 15OECh. 10.4 - 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Prob. 27WECh. 10.5 - Prob. 28WECh. 10.5 - Prob. 29WECh. 10.5 - Prob. 30WECh. 10.5 - Prob. 31WECh. 10.5 - Prob. 32WECh. 10.5 - Prob. 33WECh. 10.5 - Prob. 34WECh. 10.5 - Prob. 35WECh. 10.5 - Prob. 36WECh. 10.5 - Prob. 37WECh. 10.5 - Prob. 38WECh. 10.5 - Prob. 39WECh. 10.5 - Prob. 40WECh. 10.5 - Prob. 41WECh. 10.5 - Prob. 42WECh. 10.5 - Prob. 43WECh. 10.5 - Prob. 44WECh. 10.5 - Prob. 45WECh. 10.5 - Prob. 46WECh. 10.5 - Prob. 47WECh. 10.5 - Prob. 48WECh. 10.5 - Prob. 49WECh. 10.5 - Prob. 50WECh. 10.5 - Prob. 51WECh. 10.5 - Prob. 1MRECh. 10.5 - Prob. 2MRECh. 10.5 - Prob. 3MRECh. 10.5 - Prob. 4MRECh. 10.5 - Prob. 5MRECh. 10.5 - Prob. 6MRECh. 10.5 - Prob. 7MRECh. 10.5 - Prob. 8MRECh. 10.5 - Prob. 9MRECh. 10.5 - Prob. 10MRECh. 10.5 - Prob. 11MRECh. 10.5 - Prob. 12MRECh. 10.5 - Prob. 13MRECh. 10.5 - Prob. 1STCh. 10.5 - Prob. 2STCh. 10.5 - Prob. 3STCh. 10.5 - Prob. 4STCh. 10.5 - Prob. 5STCh. 10.5 - Prob. 6STCh. 10.5 - Prob. 7STCh. 10.6 - Prob. 1OECh. 10.6 - Prob. 2OECh. 10.6 - Prob. 3OECh. 10.6 - Prob. 4OECh. 10.6 - Prob. 5OECh. 10.6 - Prob. 6OECh. 10.6 - Prob. 7OECh. 10.6 - Prob. 8OECh. 10.6 - Prob. 9OECh. 10.6 - Prob. 10OECh. 10.6 - Prob. 11OECh. 10.6 - Prob. 12OECh. 10.6 - Prob. 13OECh. 10.6 - Prob. 14OECh. 10.6 - Prob. 15OECh. 10.6 - Prob. 16OECh. 10.6 - Prob. 1WECh. 10.6 - Prob. 2WECh. 10.6 - Prob. 3WECh. 10.6 - Prob. 4WECh. 10.6 - Prob. 5WECh. 10.6 - Prob. 6WECh. 10.6 - Prob. 7WECh. 10.6 - Prob. 8WECh. 10.6 - Prob. 9WECh. 10.6 - Prob. 10WECh. 10.6 - Prob. 11WECh. 10.6 - Prob. 12WECh. 10.6 - Prob. 13WECh. 10.6 - Prob. 14WECh. 10.6 - Prob. 15WECh. 10.6 - Prob. 16WECh. 10.6 - Prob. 17WECh. 10.6 - Prob. 18WECh. 10.6 - Prob. 19WECh. 10.6 - Prob. 20WECh. 10.6 - Prob. 21WECh. 10.6 - Prob. 22WECh. 10.6 - Prob. 23WECh. 10.6 - Prob. 24WECh. 10.6 - Prob. 25WECh. 10.6 - Prob. 26WECh. 10.6 - Prob. 27WECh. 10.6 - Prob. 28WECh. 10.6 - Prob. 29WECh. 10.6 - Prob. 30WECh. 10.6 - Prob. 31WECh. 10.6 - Prob. 32WECh. 10.6 - Prob. 33WECh. 10.6 - Prob. 34WECh. 10.6 - Prob. 35WECh. 10.6 - Prob. 36WECh. 10.6 - Prob. 37WECh. 10.6 - Prob. 38WECh. 10.6 - Prob. 39WECh. 10.6 - Prob. 40WECh. 10.6 - Prob. 41WECh. 10.6 - Prob. 42WECh. 10.7 - Prob. 1OECh. 10.7 - Prob. 2OECh. 10.7 - Prob. 3OECh. 10.7 - Prob. 4OECh. 10.7 - Prob. 1PCh. 10.7 - Prob. 2PCh. 10.7 - Prob. 3PCh. 10.7 - Prob. 4PCh. 10.7 - Prob. 5PCh. 10.7 - Prob. 6PCh. 10.7 - Prob. 7PCh. 10.7 - Prob. 8PCh. 10.7 - Prob. 9PCh. 10.7 - Prob. 10PCh. 10.7 - Prob. 11PCh. 10.7 - Prob. 12PCh. 10.7 - Prob. 13PCh. 10.7 - Prob. 14PCh. 10.7 - Prob. 15PCh. 10.7 - Prob. 16PCh. 10.7 - Prob. 17PCh. 10.7 - Prob. 18PCh. 10.7 - Prob. 19PCh. 10.7 - Prob. 20PCh. 10.7 - Prob. 21PCh. 10.7 - Prob. 22PCh. 10.7 - Prob. 1MRECh. 10.7 - Prob. 2MRECh. 10.7 - Prob. 3MRECh. 10.7 - Prob. 4MRECh. 10.7 - Prob. 5MRECh. 10.7 - Prob. 6MRECh. 10.7 - Prob. 7MRECh. 10.7 - Prob. 8MRECh. 10.7 - Prob. 9MRECh. 10.7 - Prob. 10MRECh. 10.7 - Prob. 11MRECh. 10.7 - Prob. 12MRECh. 10.8 - Prob. 1OECh. 10.8 - Prob. 2OECh. 10.8 - Prob. 3OECh. 10.8 - Prob. 4OECh. 10.8 - Prob. 5OECh. 10.8 - Prob. 6OECh. 10.8 - 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