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Concept explainers
a.
To find: The standard form of equation
a.
![Check Mark](/static/check-mark.png)
Answer to Problem 63E
The standard form of the equation
Explanation of Solution
Given information:
The given equation is
Calculation:
The equation of the conic is as.
Here
Calculate the value of
Calculate the transformed equation.
Solve the above equation.
Solve the above equation.
Therefore, the standard form of the equation
b.
To find:The distance from the vertex of the cross section to the receiver.
b.
![Check Mark](/static/check-mark.png)
Answer to Problem 63E
The distance from the vertex of the cross section to the receiver is
Explanation of Solution
Given information:
The given equation is
Calculation:
Compare the given equation
Therefore, the distance from the vertex of the cross section to the receiver is
Chapter 10 Solutions
Precalculus with Limits
- Car A starts from rest at t = 0 and travels along a straight road with a constant acceleration of 6 ft/s^2 until it reaches a speed of 60ft/s. Afterwards it maintains the speed. Also, when t = 0, car B located 6000 ft down the road is traveling towards A at a constant speed of 80 ft/s. Determine the distance traveled by Car A when they pass each other.Write the solution using pen and draw the graph if needed.arrow_forwardThe velocity of a particle moves along the x-axis and is given by the equation ds/dt = 40 - 3t^2 m/s. Calculate the acceleration at time t=2 s and t=4 s. Calculate also the total displacement at the given interval. Assume at t=0 s=5m.Write the solution using pen and draw the graph if needed.arrow_forwardThe velocity of a particle moves along the x-axis and is given by the equation ds/dt = 40 - 3t^2 m/s. Calculate the acceleration at time t=2 s and t=4 s. Calculate also the total displacement at the given interval. Assume at t=0 s=5m.Write the solution using pen and draw the graph if needed.arrow_forward
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