Comparison tests Use the Comparison Test or Limit Comparison Test to determine whether the following series converge.
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Calculus: Early Transcendentals (3rd Edition)
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- select the correct answer and explain step by steparrow_forwardMatch the following series with the series below in which you can compare using the Limit Comparison Test. Then determine whether the series converge or diverge. n-1 1. ? 2. ? 3. ? 4. ? A. n=1 < iM8 ∞ n=1 n=1 n n+6 n² -2 (2-²715) +5 n=1 1 +4 5 B. n - n² + 1 ∞ n=1 n2¹ C. n=1 1 n³' and D. Σ(;) Does this series converge or diverge? ? Does this series converge or diverge? ? Does this series converge or diverge? ? Does this series converge or diverge? ? <arrow_forwardMake a guess abou the convergence or divergence of the series, and confirm your guessing using the Comparison Test. Please indicate the solution.arrow_forward
- Determine whether the series converges or divergesarrow_forward00 Does the seriesE(- 1n+12+n° n4 converge absolutely, converge conditionally, or diverge? n= 1 Choose the correct answer below and, if necessary, fill in the answer box to complete your choice. O A. The series converges absolutely per the Comparison Test with > 00 n4 n= 1 B. The series diverges because the limit used in the Ratio Test is not less than or equal to 1. OC. The series converges conditionally per the Alternating Series Test and the Comparison Test with n= 1 D. The series converges absolutely because the limit used in the nth-Term Test is E. The series diverges because the limit used in the nth-Term Test does not exist. O F. The series converges conditionally per the Alternating Series Test and because the limit used in the Ratio Test isarrow_forward