To find: whether the series converges or diverges.
Answer to Problem 22E
Since, the
Explanation of Solution
Given information:
Given expression:
Calculation:
The Integral Test
Let
Given series
Here, the Integral Test applies because
It is a continuous, positive, decreasing function of
We have,
Since, the integral diverges, hence from the statement of Integral test series also diverges.
Chapter 10 Solutions
Calculus: Graphical, Numerical, Algebraic
Additional Math Textbook Solutions
Thomas' Calculus: Early Transcendentals (14th Edition)
Precalculus
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Calculus and Its Applications (11th Edition)
Precalculus
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