Explanation Given: The total height of the beam's cross-sectional area is 200 mm . The total width of the beam's cross-sectional area is 200 mm . Explanation: To calculate the moment of inertia for the beam’s cross-sectional area about the x axis, subdivide the cross-sectional area into 3 segments as follows: Part 1: Rectangle Part 2: Rectangle Part 3: Rectangle Show the subdivided beam's cross-sectional area along with their respective centroids as in Figure 1: From Figure (1), Write the height and the width of the rectangle in part 1: b 1 = 3 0 mm h 1 = 17 0 mm Here, the height of rectangle in part 1 is h 1 and the width of rectangle in part 1 is b 1 . Write the height and width of the rectangle in part 2: b 2 = 17 0 mm h 2 = 3 0 mm Here, the height of the rectangle in part 2 is h 2 and the width of the rectangle in part 2 is b 2 . Write the height and width of the rectangle in part 3: b 3 = 3 0 mm h 3 = 10 0 mm Here, the height of the rectangle in part 3 is h 3 and the width of the rectangle in part 3 is b 3 . Calculations: Calculate the distance between centroid and y axis about the x axis for rectangle in part 1: d x 1 = h 2 + h 1 2 (I) Substitute 30 mm for h 2 and 170 mm for h 1 in Equation (I). d x 1 = 30 + 170 2 = 115 mm Calculate the distance between centroid and y axis about the axis for the rectangle in part 2: d x 2 = h 2 2 (II) Substitute 30 mm for h 2 in Equation (II). d x 2 = 30 2 = 15 mm Calculate the distance between centroid and y axis about the x axis for rectangle in part 3: d x 3 = h 3 2 (III) Substitute 100 mm for h 3 in Equation (III). d x 3 = 100 2 = 50 mm Conclusion: Apply parallel axis theorem in Figure 1: I y = ∑ I ¯ y ′ + A d x 2 = ( I ¯ y ′ + A d x 2 ) 1 + ( I ¯ y ′ + A d x 2 ) 2 + ( I ¯ y ′ + A d x 2 ) 3 =

13th Edition

ISBN: 9780132915540

Author: Russell C. Hibbeler

Publisher: Prentice Hall

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Moment of Inertia

Inertia can be termed as a resistance offered by a body to change its state. A rigid body initially at rest will apply resistance when acted by an external force that tends to change its state of rest or velocity, or a body initially at motion will provi…

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Chapter 10.4, Problem 43P

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The moment of inertia of the beam's cross-sectional area about the y axis.

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Chapter 10.4, Problem 42P

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Ch. 10.3 - Determine the moment of inertia of the shaded area...Ch. 10.3 - Determine the moment of inertia of the shaded area...Ch. 10.3 - Determine the moment of inertia of the shaded area...Ch. 10.3 - Determine the moment of inertia of the shaded area...Ch. 10.3 - Prob. 1P Ch. 10.3 - Prob. 2P Ch. 10.3 - Prob. 3P Ch. 10.3 - Prob. 4P Ch. 10.3 - Prob. 5P Ch. 10.3 - Prob. 6P

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