Explanation Given: The total height of the beam’s cross sectional area is 400 mm . The total width of the beam’s cross sectional area is 300 mm . To calculate the moment of inertia of the beam’s cross sectional area about the y axis, subdivide the cross sectional area into 2 segments as follows: Part 1: rectangle Part 2: rectangle Show the subdivided beam’s area along with their respective centroids as in Figure 1. From Figure (1), Write the height and width of the rectangle in part 1. b 1 = 360 mm h 1 = 20 mm Here, the height of the rectangle in part 1 is h 1 and the width of the rectangle in part 1 is b 1 . Write the height and width of the rectangle in part 2. b 2 = 2 × 20 = 4 0 mm h 2 = 300 mm Here, the height of the rectangle in part 2 is h 2 and the width of the rectangle in part 2 is b 2 . Conclusion: From Figure (1), it is clear that the y axis passes through the centroids of segments 1 and 2. Compute the moment of inertia about x axis. I y = I ¯ y ′ 1 + I ¯ y ′ 2 = 1 12 b 1 h 1 3 + 1 12 b 2 h 2 3 (I) Here, the moment of inertia for the beam’s cross-sect

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Inertia can be termed as a resistance offered by a body to change its state. A rigid body initially at rest will apply resistance when acted by an external force that tends to change its state of rest or velocity, or a body initially at motion will provi…

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Chapter 10.4, Problem 37P

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The moment of inertia about the y axis.

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Chapter 10.4, Problem 36P

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The moment of inertia about the y axis.

Solution Summary: The author explains the moment of inertia of the beam's cross sectional area about the y axis.

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