Essentials of Statistics for Business and Economics
9th Edition
ISBN: 9780357118191
Author: David R. Anderson, Dennis J. Sweeney, Thomas A. Williams
Publisher: Cengage Learning US
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Chapter 10.4, Problem 31E
Impact of Pinterest on Purchase Decisions. Forbes reports that women trust recommendations from Pinterest more than recommendations from any other social network platform (https://www.forbes.com/sites/marketshare/2012/03/20/why-brand-managers-need-to-take-an-interest-in -pinterest/#5e3b22fb6375). But does trust in Pinterest differ by gender? The following sample data show the number of women and men who stated in a recent sample that they trust recommendations made on Pinterest.
- a. What is the point estimate of the proportion of women who trust recommendations made on Pinterest?
- b. What is the point estimate of the proportion of men who trust recommendations made on Pinterest?
- c. Provide a 95% confidence
interval estimate of the difference between the proportion of women and men who trust recommendations made on Pinterest.
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Students have asked these similar questions
Compute the relative risk of falling for the two groups (did not stop walking vs. did stop). State/interpret your result verbally.
Microsoft Excel include formulas
Question 1
The data shown in Table 1 are and R values for 24 samples of size n = 5 taken from a process producing
bearings. The measurements are made on the inside diameter of the bearing, with only the last three decimals
recorded (i.e., 34.5 should be 0.50345).
Table 1: Bearing Diameter Data
Sample Number
I
R
Sample Number
I R
1
34.5
3
13
35.4
8
2
34.2
4
14
34.0
6
3
31.6
4
15
37.1
5
4
31.5
4
16
34.9
7
5
35.0
5
17
33.5
4
6
34.1
6
18
31.7
3
7
32.6
4
19
34.0
8
8
33.8
3
20
35.1
9
34.8
7
21
33.7
2
10
33.6
8
22
32.8
1
11
31.9
3
23
33.5
3
12
38.6 9
24
34.2
2
(a) Set up and R charts on this process. Does the process seem to be in statistical control? If necessary,
revise the trial control limits. [15 pts]
(b) If specifications on this diameter are 0.5030±0.0010, find the percentage of nonconforming bearings pro-
duced by this process. Assume that diameter is normally distributed. [10 pts]
1
Chapter 10 Solutions
Essentials of Statistics for Business and Economics
Ch. 10.1 - The following results come from two independent...Ch. 10.1 - 2. Consider the following hypothesis test.
The...Ch. 10.1 - Consider the following hypothesis test....Ch. 10.1 - 4. Condé Nast Traveler conducts an annual survey...Ch. 10.1 - The USA Today reports that the average expenditure...Ch. 10.1 - Hotel Price Comparison. Suppose that you are...Ch. 10.1 - Supermarket Customer Satisfaction. Consumer...Ch. 10.1 - Increases in Customer Satisfaction. Will improving...Ch. 10.2 - The following results are for independent random...Ch. 10.2 - Consider the following hypothesis test:...
Ch. 10.2 - Consider the following data for two independent...Ch. 10.2 - Miles Driven Per Day. The U.S. Department of...Ch. 10.2 - Annual Cost of College. The increasing annual cost...Ch. 10.2 - Salaries of Recent College Graduates. The Tippie...Ch. 10.2 - Hotel Prices. Hotel room pricing changes over time...Ch. 10.2 - Effect of Parents’ Education on Student SAT...Ch. 10.2 - Comparing Financial Consultant Ratings....Ch. 10.2 - Comparing Length of Flight Delays. The success of...Ch. 10.3 - Consider the following hypothesis test.
The...Ch. 10.3 - The following data are from matched samples taken...Ch. 10.3 - Television Commercials and Product Purchase...Ch. 10.3 - First-Quarter Stock Market Performance. The price...Ch. 10.3 - Credit Card Expenditures. Bank of America’s...Ch. 10.3 - Domestic Airfare. The Global Business Travel...Ch. 10.3 - SAT Scores. The College Board SAT college entrance...Ch. 10.3 - PGA Tour Scores. Scores in the first and fourth...Ch. 10.3 - Price Comparison of Smoothie Blenders. A personal...Ch. 10.4 - Consider the following results for independent...Ch. 10.4 - Consider the hypothesis test
The following...Ch. 10.4 - Corporate Hiring Outlook. A Businessweek/Harris...Ch. 10.4 - Impact of Pinterest on Purchase Decisions. Forbes...Ch. 10.4 - Mislabeled Fish. Researchers with Oceana, a group...Ch. 10.4 - Voter Turnout. Minnesota had the highest turnout...Ch. 10.4 - Oil Well Drilling. Oil wells are expensive to...Ch. 10.4 - Hotel Occupancy Rates. Tourism is extremely...Ch. 10.4 - Gender Differences in Raise or Promotion...Ch. 10.4 - Default Rates on Bank Loans. Carl Allen and Norm...Ch. 10 - Supermarket Checkout Lane Design. Safegate Foods,...Ch. 10 - SUV Lease Payments. Statista reports that the...Ch. 10 - Load Versus No-Load Mutal Funds. Mutual funds are...Ch. 10 - Kitchen Versus Bedroom Remodeling Costs. The...Ch. 10 - Effect of Siblings on SAT Scores. In Born...Ch. 10 - Change in Financial Security. Country Financial, a...Ch. 10 - Differences in Insurance Claims Based on Marital...Ch. 10 - Drug-Resistant Gonorrhea. Each year, more than 2...Ch. 10 - News Access Via Computer. The American Press...Ch. 10 - Par, Inc., is a major manufacturer of golf...
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- 4. (5 pts) Conduct a chi-square contingency test (test of independence) to assess whether there is an association between the behavior of the elderly person (did not stop to talk, did stop to talk) and their likelihood of falling. Below, please state your null and alternative hypotheses, calculate your expected values and write them in the table, compute the test statistic, test the null by comparing your test statistic to the critical value in Table A (p. 713-714) of your textbook and/or estimating the P-value, and provide your conclusions in written form. Make sure to show your work. Did not stop walking to talk Stopped walking to talk Suffered a fall 12 11 Totals 23 Did not suffer a fall | 2 Totals 35 37 14 46 60 Tarrow_forwardQuestion 2 Parts manufactured by an injection molding process are subjected to a compressive strength test. Twenty samples of five parts each are collected, and the compressive strengths (in psi) are shown in Table 2. Table 2: Strength Data for Question 2 Sample Number x1 x2 23 x4 x5 R 1 83.0 2 88.6 78.3 78.8 3 85.7 75.8 84.3 81.2 78.7 75.7 77.0 71.0 84.2 81.0 79.1 7.3 80.2 17.6 75.2 80.4 10.4 4 80.8 74.4 82.5 74.1 75.7 77.5 8.4 5 83.4 78.4 82.6 78.2 78.9 80.3 5.2 File Preview 6 75.3 79.9 87.3 89.7 81.8 82.8 14.5 7 74.5 78.0 80.8 73.4 79.7 77.3 7.4 8 79.2 84.4 81.5 86.0 74.5 81.1 11.4 9 80.5 86.2 76.2 64.1 80.2 81.4 9.9 10 75.7 75.2 71.1 82.1 74.3 75.7 10.9 11 80.0 81.5 78.4 73.8 78.1 78.4 7.7 12 80.6 81.8 79.3 73.8 81.7 79.4 8.0 13 82.7 81.3 79.1 82.0 79.5 80.9 3.6 14 79.2 74.9 78.6 77.7 75.3 77.1 4.3 15 85.5 82.1 82.8 73.4 71.7 79.1 13.8 16 78.8 79.6 80.2 79.1 80.8 79.7 2.0 17 82.1 78.2 18 84.5 76.9 75.5 83.5 81.2 19 79.0 77.8 20 84.5 73.1 78.2 82.1 79.2 81.1 7.6 81.2 84.4 81.6 80.8…arrow_forwardName: Lab Time: Quiz 7 & 8 (Take Home) - due Wednesday, Feb. 26 Contingency Analysis (Ch. 9) In lab 5, part 3, you will create a mosaic plot and conducted a chi-square contingency test to evaluate whether elderly patients who did not stop walking to talk (vs. those who did stop) were more likely to suffer a fall in the next six months. I have tabulated the data below. Answer the questions below. Please show your calculations on this or a separate sheet. Did not stop walking to talk Stopped walking to talk Totals Suffered a fall Did not suffer a fall Totals 12 11 23 2 35 37 14 14 46 60 Quiz 7: 1. (2 pts) Compute the odds of falling for each group. Compute the odds ratio for those who did not stop walking vs. those who did stop walking. Interpret your result verbally.arrow_forward
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