A cable hanging freely between two vertical support beams forms a curve called a catenary. The shape of a catenary resembles a parabola but mathematically the two functions are quite different. a . On a graphing utility, graph a catenary defined by y = 1 2 e x + e − x and graph the parabola defined by y = x 2 + 1 . b. A catenary and a parabola are so similar in shape that we can often use a parabolic curve to approximate the shape of a catenary. For example, a bridge has cables suspended from a larger approximately parabolic cable. Take the origin at a point on the road directly below the vertex and write an equation of the parabolic cable. c. Determine the focal length of the parabolic cable. d. Determine the length of the vertical support cable 100 ft from the vertex. Round to the nearest tenth of a foot.
A cable hanging freely between two vertical support beams forms a curve called a catenary. The shape of a catenary resembles a parabola but mathematically the two functions are quite different. a . On a graphing utility, graph a catenary defined by y = 1 2 e x + e − x and graph the parabola defined by y = x 2 + 1 . b. A catenary and a parabola are so similar in shape that we can often use a parabolic curve to approximate the shape of a catenary. For example, a bridge has cables suspended from a larger approximately parabolic cable. Take the origin at a point on the road directly below the vertex and write an equation of the parabolic cable. c. Determine the focal length of the parabolic cable. d. Determine the length of the vertical support cable 100 ft from the vertex. Round to the nearest tenth of a foot.
Solution Summary: The author explains how to graph a catenary and parabola using the Ti-83 graphing calculator.
A cable hanging freely between two vertical support beams forms a curve called a catenary. The shape of a catenary resembles a parabola but mathematically the two functions are quite different.
a. On a graphing utility, graph a catenary defined by
y
=
1
2
e
x
+
e
−
x
and graph the parabola defined by
y
=
x
2
+
1
.
b. A catenary and a parabola are so similar in shape that we can often use a parabolic curve to approximate the shape of a catenary. For example, a bridge has cables suspended from a larger approximately parabolic cable. Take the origin at a point on the road directly below the vertex and write an equation of the parabolic cable.
c. Determine the focal length of the parabolic cable.
d. Determine the length of the vertical support cable
100
ft
from the vertex. Round to the nearest tenth of a foot.
1. A bicyclist is riding their bike along the Chicago Lakefront Trail. The velocity (in
feet per second) of the bicyclist is recorded below. Use (a) Simpson's Rule, and (b)
the Trapezoidal Rule to estimate the total distance the bicyclist traveled during the
8-second period.
t
0 2
4 6 8
V
10 15
12 10 16
2. Find the midpoint rule approximation for
(a) n = 4
+5
x²dx using n subintervals.
1° 2
(b) n = 8
36
32
28
36
32
28
24
24
20
20
16
16
12
8-
4
1
2
3
4
5
6
12
8
4
1
2
3
4
5
6
=
5 37
A 4 8 0.5
06
9
Consider the following system of equations, Ax=b :
x+2y+3z - w = 2
2x4z2w = 3
-x+6y+17z7w = 0
-9x-2y+13z7w = -14
a. Find the solution to the system. Write it as a parametric equation. You can use a
computer to do the row reduction.
b. What is a geometric description of the solution? Explain how you know.
c. Write the solution in vector form?
d. What is the solution to the homogeneous system, Ax=0?
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