Explanation Given: The mean x ¯ = 50 and the standard deviation s = 6 . Calculation: The mean x ¯ = 50 and the standard deviation s = 6 . So, the value of k for the number less than 32 o r m o r e t h a n 68 , x ¯ − k × s = 32 50 − 6 k = 32 6 k = 18 k = 3 Therefore, the number 32 i s 3 standard deviation below the mean 50 , and the number 68 is 3 standard deviation above the mean 50

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Author: Lial

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Chapter 10.3, Problem 21E

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To calculate: The number of percentages which is less than 32 or more than 68 using Chebyshev’s theorem.

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Chapter 10.3, Problem 20E

Chapter 10.3, Problem 22E

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The number of percentages which is less than 32 o r m o r e t h a n 68 using Chebyshev’s theorem.

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To calculate: The number of percentages which is less than 32 or more than 68 using Chebyshev’s theorem.

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Chapter 10 Solutions